Convert char to cell

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António
António 2014-12-30
编辑: David Young 2014-12-30
I want to intruduce data in a table but when i run the program it says that conversion to cell from char is not possible. Did someone knows what is wrong in this code?
ze1.Nome(end+1)=input('Introduza o seu nome: ', 's');
ze1.Aperlido(end+1)=input('Introduza o seu apelido: ','s');
ze1.Categoria(end+1)=input('Introduza a sua categoria(Aluno, Docente ou Feuncionário): ','s');
ze1.Numero(end+1)=input('Introduza o seu numero: ','s');
ze1.Mail(end+1)=input('Introduza o seu e-mail: ','s');
ze1.Telefone(end+1)=input('Introduza o seu nº de telefone: ','s');
Thank you all

采纳的回答

David Young
David Young 2014-12-30
编辑:David Young 2014-12-30
Assuming that ze1.Nome is already a cell array, all you need to do is to replace the round brackets used for indexing it with curly brackets. This then assigns the string to the contents of a cell, rather than trying to convert the string to a cell. Like this:
ze1.Nome{end+1} = input('Introduza o seu nome: ', 's');
and the same for the other fields.
You should also consider changing the way you store the data. Instead of having a scalar struct with a cell array stored at each field, you could have a struct array with a string stored at each field. Then the line above would be
ze1(end+1).Nome = input('Introduza o seu nome: ', 's');
which may simplify some later processing. However, there will need to be changes earlier in the program to set the array up consistently with this.

更多回答(1 个)

Azzi Abdelmalek
Azzi Abdelmalek 2014-12-30
ze1=struct('Nome',[],'Aperlido',[],'Categoria',[],'Numero',[],'Mail',[],'Telefone',[])
ze1.Nome{end+1}=input('Introduza o seu nome: ', 's');
ze1.Aperlido{end+1}=input('Introduza o seu apelido: ','s');
ze1.Categoria{end+1}=input('Introduza a sua categoria(Aluno, Docente ou Feuncionário): ','s');
ze1.Numero{end+1}=input('Introduza o seu numero: ','s');
ze1.Mail{end+1}=input('Introduza o seu e-mail: ','s');
ze1.Telefone{end+1}=input('Introduza o seu nº de telefone: ','s');

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