Can I partition a matrix ito several seperated parts ?

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omar th
omar th 2022-3-31
评论： omar th 2022-4-1
can I partition this matrix into 4 parts ?
assume this matrix 29X1, A = [2;2;-3;4;5;6;7;-8;9;-6;5;4;-2;1;3;-9;8;7;4;-5;6;3;2;-1;4;-7;-8;5;-6];
so, I want to group this matrix into 4 seperated groups such as B=7X1, C=7X1, D=7X1, and E=8X1 ?

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Voss
Voss 2022-3-31
A = [2;2;-3;4;5;6;7;-8;9;-6;5;4;-2;1;3;-9;8;7;4;-5;6;3;2;-1;4;-7;-8;5;-6];
% maybe this:
B = A(1:7);
C = A(8:14);
D = A(15:21);
E = A(22:29);
% or maybe this:
B = A(2:4:end);
C = A(3:4:end);
D = A(4:4:end);
E = A(1:4:end);
% etc., many other partitionings are possible
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Walter Roberson
Walter Roberson 2022-4-1
Ah, I don't think there was any way any of us could have guessed you wanted to select in that order.
omar th
omar th 2022-4-1
actually its not exactly in that order for sure i changed it, but this approach worked in my assumption
thanks again

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Walter Roberson
Walter Roberson 2022-3-31
Ran in:
A = [2;2;-3;4;5;6;7;-8;9;-6;5;4;-2;1;3;-9;8;7;4;-5;6;3;2;-1;4;-7;-8;5;-6];
parts = mat2cell(A, [7, 7, 7, 8], 1);
[B, C, D, E] = parts{:};
whos
Name Size Bytes Class Attributes A 29x1 232 double B 7x1 56 double C 7x1 56 double D 7x1 56 double E 8x1 64 double parts 4x1 648 cell
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Walter Roberson
Walter Roberson 2022-3-31
Ran in:
Your desired outcome is not defined. Do you always want 4 blocks, and the first three of them should be equal, and the last should absorb any extra capacity ?
A = randi([-9 9], 35, 1);
nrow = size(A,1);
each = floor(nrow/4);
parts = mat2cell(A, [each, each, each, nrow - 3*each], 1);
[B, C, D, E] = parts{:};
whos
Name Size Bytes Class Attributes A 35x1 280 double B 8x1 64 double C 8x1 64 double D 8x1 64 double E 11x1 88 double each 1x1 8 double nrow 1x1 8 double parts 4x1 696 cell
That gives 8, 8, 8, 11.
But perhaps you would instead prefer 9, 9, 9, 8 -- in which the last matrix might be shorter, but the distribution is more even.

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