Adressing

Hello, If i have:
A=[1 2 3 ;7 5 3;9 8 3;11 53 45]
A =
1 2 3
7 5 3
9 8 3
11 53 45
and i do
>> A(9)
ans =
3
How can i know the row and coloumn through its index value ???
Thanks

 采纳的回答

Fangjun Jiang
Fangjun Jiang 2011-9-27

0 个投票

help sub2ind
help ind2sub
[row,col]=ind2sub(size(A),9)
I guess you mean this:
A=[1 2 3 ;7 5 3;9 8 3;11 53 45];
[Row,Col]=find(A==9)

3 个评论

developer
developer 2011-9-27
its not working :(
What do you mean? You can't run this?
A=magic(3);[row,col]=ind2sub(size(A),9)
Okay, I see! See update.

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