How i can code this equation ?

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Iasonas Vasios 2022-4-1

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回答： Santosh Fatale 2022-4-4

I am working on my thesis in biomedical engineering and i am stuck in coding the following equation:

I know the values of Sn6 ,f and d. When i try to calcutale the above by using this code ( Sn7=symsum(Sn6*(f-(m/d)),m,lower bound ,upper bound)) i get an error. I don't know how to and the lower bound correctly.

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Iasonas Vasios 2022-4-1

The Sn6 value, is a matrix 1x43 double

Tala 2022-4-1

编辑：Tala 2022-4-1

在 MATLAB Online 中打开

infinity is a mathematical concept, for engineering tasks, I would say you want to look at order of magnitutes. Depending on the values of f and d, you could accept an uncertanity and truncate your sum, and say sum +/- error. In

one could choose infinity=1000 and use something like this

SN6=rand(1,43);
f=rand(1,1);
d=rand(1,1);
summ=zeros(1,43);
yourinf=1000;
for m=-yourinf:yourinf
u=SN6.*(f-(m/d));
SN7=summ+u;
end

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Answer 1

Santosh Fatale 2022-4-4

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Hi Iasonas,

I understand that you want to implement following equation in MATLAB using “Symbolic Math Toolbox”. I assume that variables

, f, and d are known to you. The above equation can be implemented as follows:

syms m f;

SN7(f) = symsum(SN6*(f - (m/d)),m,lowerBound,upperBound)

f = rand(1,1) % replace it.

SN7(f)

As per the equation, the lowerBound and upperBound for summation are “

” and “+∞”. This bounds generates “NaN” (Not a Number) result for variable

for a given value of f. It is suggested that avoid using those values and use some finite large number as an upperBound and some finite small number as a lowerBound.

I expect this solution clears the issue you are facing in implementation.