How do i make this form with matrix ?

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Ann Lee
Ann Lee 2022-4-1
评论： Voss 2022-4-1
i want to make form like this picture with code.
(first a in forloop is series a, second a in forloop is series b, third a is seriesc)
and i got syntax error.
error
>> A=work5(0.5)
error: parse error near line 21 of file C:\Users\workspace\work5.m
syntax error
>>> fprintf('y-sum series a) series b) series c); %d %d %d',y,A]
^
could you check my code?
function A=work5(x)
m=1;
for k=10:10:160
n=1:k;
a= sum(nthroot(n.^2,5)./((3.^n).*(n+1)));
A(1,m)=a;
a= sum((3*n.^2+n)/(2*n.^4+nthroot(n,2)));
A(2,m)=a;
a= sum((nthroot(37,2)*n.^3)/((2*n.^3)+(3*n.^2)));
A(3,m)=a;
m=m+1;
end
y=[10:10:160]
fprintf('y-sum series a) series b) series c); %d %d %d',y,A]

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采纳的回答

Voss
Voss 2022-4-1
Ran in:
A = work5(0.5);
y-sum series a) series b) series c) 10-sum 0.23609170 0.01834773 2.60371306 20-sum 0.23609351 0.00469013 2.80141626 30-sum 0.23609351 0.00210244 2.87601971 40-sum 0.23609351 0.00118798 2.91522735 50-sum 0.23609351 0.00076243 2.93940338 60-sum 0.23609351 0.00053046 2.95580253 70-sum 0.23609351 0.00039026 2.96765763 80-sum 0.23609351 0.00029910 2.97662765 90-sum 0.23609351 0.00023652 2.98365156 100-sum 0.23609351 0.00019171 2.98930074 110-sum 0.23609351 0.00015852 2.99394282 120-sum 0.23609351 0.00013326 2.99782508 130-sum 0.23609351 0.00011359 3.00111997 140-sum 0.23609351 0.00009797 3.00395140 150-sum 0.23609351 0.00008537 3.00641075 160-sum 0.23609351 0.00007505 3.00856683
function A=work5(x)
m=1;
y = 10:10:160;
for k = y
n=1:k;
a= sum(nthroot(n.^2,5)./((3.^n).*(n+1)));
A(1,m)=a;
a= sum((3*n.^2+n)/(2*n.^4+nthroot(n,2)));
A(2,m)=a;
a= sum((nthroot(37,2)*n.^3)/((2*n.^3)+(3*n.^2)));
A(3,m)=a;
m=m+1;
end
fprintf('y-sum\t\t%-10s\t%-10s\t%-10s\n','series a)','series b)','series c)');
fprintf('%-d-sum\t\t%10.8f\t%10.8f\t%10.8f\n',[y; A]);
end

更多回答（1 个）

KSSV
KSSV 2022-4-1
A = work5() ;
function A=work5()
m=1;
for k=10:10:160
n=1:k;
a= sum(nthroot(n.^2,5)./((3.^n).*(n+1)));
A(1,m)=a;
a= sum((3*n.^2+n)/(2*n.^4+nthroot(n,2)));
A(2,m)=a;
a= sum((nthroot(37,2)*n.^3)/((2*n.^3)+(3*n.^2)));
A(3,m)=a;
m=m+1;
end
y=10:10:160 ;
fprintf('y-sum series a) series b) series c); %d %d %d',y,A)
end

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