Store function results from for loop
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This is a project for a class.
Three variables d_o_shaft, h and w are the inputs.
Two outputs are Defl and Nf.
I'd like to store the three inputs in a 3xn matrix every time they meet a certain criteria; 1.3 <= Nf < 1.31 and Defl < .01.
This is the basic structure of my code, I simplified the equations for visual ease.
for do_shaft = .04:.001:.14
for h = .01:.001:.10
for w = .01:.001:.10
Nf = func(inputs)
Defl = func(inputs)
end
end
end
采纳的回答
Torsten
2022-4-2
i = 0;
for do_shaft = .04:.001:.14
for h = .01:.001:.10
for w = .01:.001:.10
Nf = func(inputs)
Defl = func(inputs)
if Nf >= 1.3 && Nf <= 1.31 && Defl <= 0.01
i = i + 1;
matrix(1:3,i) =[do_shaft,h,w]
end
end
end
end
4 个评论
Nicolas Caride
2022-4-2
Sorry, should be:
matrix(i,1:3) = [do_shaft,h,w]
instead of
matrix(1:3,i) = [do_shaft,h,w]
You can inspect the matrix after the loop.
Voss
2022-4-2
@Nicolas Caride It is a good idea to initialize matrix to empty before the loop (as in my answer), especially if you are running this in the base workspace. For instance, if the conditions are never met, matrix will be whatever it was before you ran this code, which may be something completely unrelated or it may not exist at all. In general, without initializing first, you're attempting to add a column (or row) to a matrix that may be the wrong size, in which case you'll run into an error.
Nicolas Caride
2022-4-2
更多回答（1 个）
Voss
2022-4-2
matrix = [];
for do_shaft = .04:.001:.14
for h = .01:.001:.10
for w = .01:.001:.10
Nf = func(inputs);
Defl = func(inputs);
if Nf >= 1.3 && Nf < 1.31 && Defl < 0.01
matrix(:,end+1) = [do_shaft; h; w];
end
end
end
end
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