Store function results from for loop

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Nicolas Caride
Nicolas Caride 2022-4-2
评论： Nicolas Caride 2022-4-2
This is a project for a class.
Three variables d_o_shaft, h and w are the inputs.
Two outputs are Defl and Nf.
I'd like to store the three inputs in a 3xn matrix every time they meet a certain criteria; 1.3 <= Nf < 1.31 and Defl < .01.
This is the basic structure of my code, I simplified the equations for visual ease.
for do_shaft = .04:.001:.14
for h = .01:.001:.10
for w = .01:.001:.10
Nf = func(inputs)
Defl = func(inputs)
end
end
end

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采纳的回答

Torsten
Torsten 2022-4-2
i = 0;
for do_shaft = .04:.001:.14
for h = .01:.001:.10
for w = .01:.001:.10
Nf = func(inputs)
Defl = func(inputs)
if Nf >= 1.3 && Nf <= 1.31 && Defl <= 0.01
i = i + 1;
matrix(1:3,i) =[do_shaft,h,w]
end
end
end
end
  4 个评论
显示 2更早的评论
Voss
Voss 2022-4-2
@Nicolas Caride It is a good idea to initialize matrix to empty before the loop (as in my answer), especially if you are running this in the base workspace. For instance, if the conditions are never met, matrix will be whatever it was before you ran this code, which may be something completely unrelated or it may not exist at all. In general, without initializing first, you're attempting to add a column (or row) to a matrix that may be the wrong size, in which case you'll run into an error.
Nicolas Caride
Nicolas Caride 2022-4-2
Thanks so much for the help. That was exactly what I needed.

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更多回答（1 个）

Voss
Voss 2022-4-2
matrix = [];
for do_shaft = .04:.001:.14
for h = .01:.001:.10
for w = .01:.001:.10
Nf = func(inputs);
Defl = func(inputs);
if Nf >= 1.3 && Nf < 1.31 && Defl < 0.01
matrix(:,end+1) = [do_shaft; h; w];
end
end
end
end

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