Histogram plot by equal time intervals

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Greek McCoy
Greek McCoy 2022-4-5
评论： Voss 2022-4-5
Dear all,
I have with my the attached dataset that I will like to plot in an equal interval time histogram.
Below here is my code:
clc
A = load ('TutorialSampleT.txt');
Time = A (:,1) ;
x = A (:,2 ) ;
y = A (:,3 ) ;
z = A (:,4 ) ;
Amplitude = A (:,5) ;
%define no of bins
noOfBins=min(Time):0.90:max(Time);
%plot histogram
histogram(Time,numel(noOfBins));
timeFormat=noOfBins;
timeFormat=timeFormat/24;
la=datestr(timeFormat,'HH:MM')
xticks(noOfBins);
xticklabels({la});
And the results:
I will be very happy if I can get some assistance with changing the time intervals to something more unifrom (an hour or 2 interval time will be perfect).
Thank you.

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采纳的回答

Voss
Voss 2022-4-5
Ran in:
clc
A = load ('TutorialSampleT.txt');
Time = A (:,1) ;
x = A (:,2 ) ;
y = A (:,3 ) ;
z = A (:,4 ) ;
Amplitude = A (:,5) ;
% interval in hours:
% interval = 0.9;
% interval = 1;
interval = 2;
%define no of bins
noOfBins=min(Time):interval:max(Time);
%plot histogram
% histogram(Time,numel(noOfBins));
histogram(Time,numel(noOfBins)-1); % number of bins in the histogram is one less than numel(noOfBins), i.e., noOfBins defines the bin edges
timeFormat=noOfBins;
timeFormat=timeFormat/24;
la=datestr(timeFormat,'HH:MM');
xticks(noOfBins);
xticklabels({la});
  2 个评论
Greek McCoy
Greek McCoy 2022-4-5
Hello,
Thank you very much for your answer.
It works perfectly well for me.
--
Sincerely,
Greek

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更多回答（1 个）

Steven Lord
Steven Lord 2022-4-5
Ran in:
Rather than specifying the number of bins you could specify the bin edges explicitly.
minutesPerDay = minutes(days(1));
T = datetime('today');
dt = T + minutes(randi(minutesPerDay, 1, 1000));
edges = T + hours(0:2:24);
histogram(dt, edges)
xticks(edges)
  1 个评论
Greek McCoy
Greek McCoy 2022-4-5
Hello,
Thank you very much for your response.
Your answer is very valuable to me and works well with my code.
I am definitely going to incorporate it in my code.
--
Sincerely,
Greek

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