Subtraction between a matrix and a column vector

5 次查看(过去 30 天)
So I have a matrix of the size 23x15 and a column vector of size 23x1. I need to subtract element 1 of the colum vector from the 1st row of the matrix, element 2 of the column vector from 2nd row of the matrix, and so on. Any suggestions about how I can do it?

采纳的回答

Riccardo Scorretti
Hi. If the matrix and the vector have compatible size (= like you mentioned), it is enough to use the minus operator:
A = rand(23,15);
x = rand(23,1);
A-x
ans = 23×15
0.2139 -0.4738 -0.0324 0.2879 -0.5164 -0.5204 -0.2573 -0.1252 -0.6030 0.0119 -0.5568 0.0707 0.1965 -0.2185 -0.3107 -0.3026 0.3745 -0.4007 -0.0694 -0.2514 -0.0244 -0.0126 -0.4829 0.1296 0.3859 0.1160 0.1024 -0.0164 -0.3397 -0.3895 -0.0364 -0.2650 -0.0361 -0.1169 -0.1134 0.6802 0.5602 0.0069 0.1628 -0.2122 -0.0523 0.5581 0.6691 0.0580 0.4566 -0.8499 -0.7361 -0.4907 -0.7858 -0.1153 -0.6816 -0.5459 -0.0587 -0.5956 -0.2459 -0.4201 -0.8757 -0.8312 -0.2901 -0.7761 -0.1458 0.3076 0.4151 0.4332 -0.2664 0.0339 -0.4702 0.4185 -0.3688 -0.0325 -0.3356 0.3817 0.0343 0.1336 -0.4908 -0.1485 -0.5956 -0.1521 -0.2995 -0.7787 -0.1461 -0.6266 -0.3964 -0.6241 -0.7282 -0.4468 -0.6754 -0.8928 -0.5799 -0.8771 -0.8125 0.1077 -0.6755 -0.7532 -0.2350 0.1244 -0.8128 -0.2916 -0.5226 -0.2108 -0.3767 -0.0239 -0.7943 -0.7744 -0.4538 -0.2816 -0.3594 -0.8926 -0.2823 -0.2469 -0.5546 0.0076 -0.3071 -0.8171 -0.3084 -0.6816 -0.9024 -0.6121 0.0152 -0.8946 0.1406 0.3451 0.3059 -0.2132 0.3232 -0.3814 0.1598 -0.4034 -0.1477 -0.2525 -0.4202 -0.4624 -0.1376 -0.5925 0.3209 0.6027 0.5138 0.2264 0.0285 -0.1912 -0.1324 0.5262 0.6078 -0.0720 0.4299 0.0051 0.4744 0.0725 -0.0732 0.4045
  1 个评论
Akshay Vivek Panchwagh
Thank you. I actually needed to repeat the other matrix (the "x" one mentioned by you here). So I did the operation using 'repmat' and it worked.

请先登录,再进行评论。

更多回答(1 个)

Torsten
Torsten 2022-4-5
B = A - x
where A is your matrix and x is your vector.

类别

Help CenterFile Exchange 中查找有关 Matrices and Arrays 的更多信息

产品


版本

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by