Error ' Index in position 2 exceeds array bounds'.how to correct this.

Question

ANCY S GEORGE 2022-4-6

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1689915-error-index-in-position-2-exceeds-array-bounds-how-to-correct-this

编辑： ANCY S GEORGE 2023-1-30

采纳的回答： Geoff Hayes

在 MATLAB Online 中打开

When run it, shows

"Index in position 2 exceeds array bounds. Index

must not exceed 2.

Error in practice (line 20)

while(abs(a(k)-a(k-1))>=0.01) && abs(b(k)-b(k-1))>=0.01 && rms(abs(A(:,k)-A(:,k-1)))>=0.01"

Please help to correct this?

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Answer 1

Geoff Hayes 2022-4-6

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https://ww2.mathworks.cn/matlabcentral/answers/1689915-error-index-in-position-2-exceeds-array-bounds-how-to-correct-this#answer_936075

编辑：Geoff Hayes 2022-4-6

在 MATLAB Online 中打开

@susan sara - in your while loop conditions

while(abs(a(k)-a(k-1))>=0.01) && abs(b(k)-b(k-1))>=0.01  && rms(abs(A(:,k)-A(:,k-1)))>=0.01

you have

rms(abs(A(:,k)-A(:,k-1)))

. At the end of the loop you do

k=k+1;

. I don't see anywhere in the code where you update A for k+1 and so I suspect the error message is originating when indexing into A on the second iteration of the loop when k is 3. You may want to review this code

for j=x(1):1:x(length(i))
    A(j,k)=((H(j))/(a(k)))-1    
    for j=y(1):1:y(length(i))
        A(j,k)=((H(j))/(b(k)))-1      
    end
    for j=z(1):1:z(length(i))
        A(j,k)=G(j)         
    end