Is there a way to get the redirect url after a https / api request?

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I'm using the Spotify API and in order to get authorization I need to get the url of the redirected page after completing the first api request.
client_id = "CLIENT_CODE"; % Specific Application client id
redirect_uri = 'REDIRECT_URL';
scope = 'user-read-private user-read-email';
response_type = 'code';
% Authorization url
auth_url = "https://accounts.spotify.com/authorize?";
auth_url = strcat(auth_url, "client_id="+client_id);
auth_url = strcat(auth_url, "&redirect_uri="+redirect_uri);
auth_url = strcat(auth_url, "&response_type="+response_type);
web(auth_url)
Right now, when you input my actual client code and redirect_url, it opens up the authorization page and then after you authorize (or don't) the page is redirect to a url like this:
REDIRECT_URL/?code=AQDkK3AcQqCnoiV37f1Ied1DjOyEINjnzKB1HA-JO7c0HIyYL2VR0PGrbawMQiKkuquXUl7UlI19VaEvDp2jzxsOF_scEItkktas0voMUgc4p2q1W8i0Kx4a_i3KB0dB6AtRO_ruQWXCVto_9ZQLn_bqJ7soiGsYN_3rLO6nheky5_VREMdzi9IVlzQg0A
This information after the 'code=' is the authorization key that I need.
Does anyone know how to retrieve this in MATLAB?

采纳的回答

Mohammad Sami
Mohammad Sami 2022-4-7
You can use the matlab.net.http interface to follow the redirects.
request = matlab.net.http.RequestMessage;
uri = matlab.net.URI('https://goo.gl/maps/co8U2mMv8zFweDzN8');
[response,completedrequest,history] = send(request,uri);
finaluri = history(end).URI;
disp(finaluri);
URI with properties: Scheme: "https" UserInfo: [0×0 string] Host: "consent.google.com" Port: [] EncodedAuthority: "consent.google.com" Path: ["" "ml"] EncodedPath: "/ml" Query: [1×6 matlab.net.QueryParameter] EncodedQuery: "continue=https://www.google.com/maps/place/Houston,%2BTX,%2BUSA/@29.8174782,-95.6814846,10z/data%3D!3m1!4b1!4m5!3m4!1s0x8640b8b4488d8501:0xca0d02def365053b!8m2!3d29.7596088!4d-95.3723145&gl=IE&m=0&pc=m&hl=en&src=1" Fragment: [0×0 string] Absolute: 1 EncodedURI: "https://consent.google.com/ml?continue=https://www.google.com/maps/place/Houston,%2BTX,%2BUSA/@29.8174782,-95.6814846,10z/data%3D!3m1!4b1!4m5!3m4!1s0x8640b8b4488d8501:0xca0d02def365053b!8m2!3d29.7596088!4d-95.3723145&gl=IE&m=0&pc=m&hl=en&src=1"
  4 个评论
Hank Helmers
Hank Helmers 2022-4-8
Oh ok, that's what I was afraid of but wasn't sure. Thank you! Appreciate the help!

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