Why reshaping the matrix gives entirely different plots while using pcolor()

2 次查看（过去 30 天）

显示更早的评论

Mathan 2022-4-6

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1690430-why-reshaping-the-matrix-gives-entirely-different-plots-while-using-pcolor

评论： Mathan 2022-4-7

采纳的回答： Walter Roberson

在 MATLAB Online 中打开

Hello,

I was trying to plot 3 variables with two of them representing the X and Y axes while the third one is used to denote the color, using the pcolor function. I however find that whenever I change the dimensions of the matrix by reshaping them and try plotting again, I get entirely different plots. I was wondering why that is happening - after all its the same datapoints which are being plotted against each other everytime (no matter what the dimension of the matrix is) , how come a mere change in the dimensions of the matrix give different results?

Following is the code which I tried (given for example):

M = randi([1 100],13, 21);                % original matrices
N = randi([200 500],13, 21);
P = randi([700 1000],13, 21);
M1 = reshape(M,3,[]);                     % reshaped matrices from the original matrices
N1 = reshape(N,3,[]);
P1 = reshape(P,3,[]);
M2 = reshape(M,39,[]);                   % reshaped matrices from the original matrices
N2 = reshape(N,39,[]);
P2 = reshape(P,39,[]);
figure(1);
pcolor(M,N,P);
figure(2);
pcolor(M1, N1, P1);
figure(3);
pcolor(M2, N2, P2);

Thank you.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Walter Roberson 2022-4-6

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1690430-why-reshaping-the-matrix-gives-entirely-different-plots-while-using-pcolor#answer_936595

pcolor() is equivalent to surf() followed by view(90) .

surf() does not use the input data directly to compute face color. Instead, surf() uses the input data as indicating the vertices, and does a bilinear interpolation to get the value to use for the face color.

When you reshape() you change the relative order of the nodes, and so change which vertices are combined for a particular face. But because of the interpolation to get the actual face color, that changes the face colors.

7 个评论
显示 5更早的评论隐藏 5更早的评论

Walter Roberson 2022-4-7

在 MATLAB Online 中打开

imagesc('XData', [M(1,1), M(end,end)], 'YData', [N(1,1),N(end,end)], 'CData', P)

Mathan 2022-4-7

在 MATLAB Online 中打开

It still gives out the same result (i.e. different plots whenever reshaping is done). The code is as follows:

M = randi([1 100],13, 21);
N = randi([200 500],13, 21);
P = randi([700 1000],13, 21);
M1 = reshape(M,3,[]);
N1 = reshape(N,3,[]);
P1 = reshape(P,3,[]);
M2 = reshape(M,39,[]);
N2 = reshape(N,39,[]);
P2 = reshape(P,39,[]);
M3 = reshape(M.',1,[]);
N3 = reshape(N,1,[]);
P3 = reshape(P,1,[]);
figure(1);
imagesc('XData', [M(1,1), M(end,end)], 'YData', [N(1,1),N(end,end)], 'CData', P)
figure(2);
imagesc('XData', [M1(1,1), M1(end,end)], 'YData', [N1(1,1),N1(end,end)], 'CData', P1)
figure(3);
imagesc('XData', [M2(1,1), M2(end,end)], 'YData', [N2(1,1),N2(end,end)], 'CData', P2)