ind() function or find() function not working

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Katherine Sadler
Katherine Sadler 2022-4-7
评论： Stephen23 2022-4-7
At first this section of code was working, and return the right indexes, but now its not working. It should be returning: ind = 3 4 but it returns ind = 1
A = [1 1 2 2 3 4 5 6 7 8 9];
a = length(A);
b = A(3)
ind = find(b)
if length(ind) == 1
bmatch = 0
elseif length(ind) > 1
bmatch = 1
else
end
It returns:
b =
2
ind =
1
bmatch =
0
Any help is greatly appreciated!
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Katherine Sadler
Katherine Sadler 2022-4-7
Oh I thought the FIND would return the index spot of 3 and 4. Thanks
Stephen23
Stephen23 2022-4-7
All FIND knows about is the scalar input that you have provided it. FIND cannot guess that that scalar array was origianally in position 3 of a larger array, nor can it guess that there were other identical values in that larger array. It only knows about the scalar element that you gave it.

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采纳的回答

Dyuman Joshi
Dyuman Joshi 2022-4-7
Use
ind = find(A==b);
%find(x) is generally used for matrices to find non-zero values.

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