How can I find the Euclidean distance between moving points?

Question

omar th 2022-4-8

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1691695-how-can-i-find-the-euclidean-distance-between-moving-points

评论： Jan 2022-4-9

I deployed number of random points with their speed and displacement, how can I make these point MOVING frequently each second,

since the Euclidean distance between these points is updated each time interval ( second) based on the coordinates of new positions ?

NumNode=2;ro=1000;center=[0 0];Initial_Direction = rand(NumNode, 1) * 2 *pi; v = 15/3.6; % [m/s] velocity of node
        theta_Node=2*pi*(rand(NumNode,1)); 
        g = 0.5 * ro + 0.5 * ro * rand(NumNode,1); % let the Nodes deployed away from the center of circle network layout
        PosNode_x=center(1)+g.*cos(theta_Node); % Initial positions
        PosNode_y=center(2)+g.*sin(theta_Node);
        PosNode = [PosNode_x ,PosNode_y]
        DX2 = [cos(Initial_Direction(:)) .* v,sin(Initial_Direction(:)) .* v]; % displacement of Node
        PosNodeNew = PosNode + DX2; % New position of node without rotating
      
        rotaion2 = [cosd(Initial_Direction), -sind(Initial_Direction); sind(Initial_Direction), cosd(Initial_Direction)]; % Rotation matrix to make the movement of node similar to move on arc
        
        % Index approach to multiply different matrix dimensions
        index=1:numel(PosNode);
        xyRotated1 = rotaion2;
        xyRotated1(index)= rotaion2(index).*PosNode(index); % rotated matrix multiply by position of node
        
        index2 = 1:numel(DX2);
        Newposss=xyRotated1;
        NewPosss(index2) = xyRotated1(index2) + DX2(index2);
        gg= NewPosss(index2);    % New position of node with rotating on arc
        
        figure(1)
        scatter(PosDrone_x,PosDrone_x,'r+')
        figure(2)
        scatter(PosDroneNew(:,1),PosDroneNew(:,2),'b*')
        figure (3)
        scatter (xyRotated1(:,1),xyRotated1(:,2),'r.')
        axis equal
        figure (4)
        scatter(NewPosss(1,:),NewPosss(1,:),'b*')
        axis equal

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Jan 2022-4-9

The question is not clear. The euclidean distance is determined by vecnorm of the difference between the point's coordinates. But which variables are meant? What is the relation between the code and your question?

请先登录，再进行评论。

请先登录，再回答此问题。

How can I find the Euclidean distance between moving points?

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

回答（0 个）

另请参阅

类别

标签

产品

版本

Community Treasure Hunt

How can I find the Euclidean distance between moving points?

1 个评论 显示 -1更早的评论隐藏 -1更早的评论

回答（0 个）

另请参阅

类别

标签

产品

版本

Community Treasure Hunt

1 个评论
显示 -1更早的评论隐藏 -1更早的评论