Cannot use find() inorder to find the index of a time in datetime array

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Mathan 2022-4-11

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https://ww2.mathworks.cn/matlabcentral/answers/1693910-cannot-use-find-inorder-to-find-the-index-of-a-time-in-datetime-array

评论： Mathan 2022-4-11

采纳的回答： Matt J

time.mat

在 MATLAB Online 中打开

Hello,

I was trying to find the index of a particular time having datetime format (attached here as time.mat). I tried the usual find() inorder to find the index of an element but am constantly getting a 0×1 empty double column vector.

For example, I tried the following.

t=load('time.mat');
time=t.a;                                       % a: [101×1 datetime]
index = find(time=='02-Dec-2014 07:05:25')

which gives me

0×1 empty double column vector.

Not sure why that is happening even though '02-Dec-2014 07:05:25' is present as the last element in the array.

Thank you for any help.

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采纳的回答

Matt J 2022-4-11

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1693910-cannot-use-find-inorder-to-find-the-index-of-a-time-in-datetime-array#answer_940270

编辑：Matt J 2022-4-11

在 MATLAB Online 中打开

time.mat

Because you have sub-second precision in "t.a",

t=load('time.mat');
t.a(end)
ans = datetime
   02-Dec-2014 07:05:25
seconds( t.a(end) - datetime('02-Dec-2014 07:05:25')) 
ans = 0.6015

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Matt J 2022-4-11

在 MATLAB Online 中打开

t=load('time.mat');
tmin=min(t.a);
time=seconds(t.a-tmin);    
N=numel(time);% a: [101×1 datetime]
index = interp1(time,1:N, seconds(datetime('02-Dec-2014 07:05:25')-tmin),'nearest')