Same loop have different vector output

1 次查看（过去 30 天）
Chaudhary P Patel
Chaudhary P Patel 2022-4-13
评论： Chaudhary P Patel 2022-4-15
Sir, when i am running this loop for f_s the first f_s1 is comming as a column vector while f_s2, 3, 4, 5, are comming as a row vector.
Please sir, suggest me where i amking the mistakes.
utdelt=([1;2;3;4;5;6;7;8;9;10;11;12;13;14;15]);
Ktts=rand(6,6);
for i=1:1:10
for n=1:1:5
if n==1
Utdelt=([zeros(3,1); (utdelt(1:3,i))]);
eval(['Utdelt',num2str(n),'=[zeros(3,1); (utdelt(1:3,i))]']);
else
Utdelt=utdelt([((1+(n-2)*3):(6+(n-2)*3)),i]);
eval(['Utdelt',num2str(n),'=[utdelt((1+(n-2)*3):(6+(n-2)*3,i)]']);
end
eval(['Ktts',num2str(n),'l']);
eval(['f_s',num2str(n),'=Ktts*Utdelt']);
end
end
  4 个评论
显示 2更早的评论
Chaudhary P Patel
Chaudhary P Patel 2022-4-13
@Walter Roberson sir, detailed problem it is there.
sir, problem is coming in this line, because f_s2, 3, 4,5 is coming as a row vector and the Utdelt value also not taking properly. So suggest me about this line.
eval(['f_s',num2str(n),'=Ktts*Utdelt']);
Stephen23
Stephen23 2022-4-13
编辑：Stephen23 2022-4-13
"Please sir, suggest me where i amking the mistakes."
The obvious mistake is that you are forcing meta-data into variable names.
That forces you into writing slow, complex, inefficient, obfuscated, buggy code that is hard to debug (which is exactly what your question demonstrates, and hopefully you are about to start to notice).

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2022-4-13
  7 个评论
显示 5更早的评论
Walter Roberson
Walter Roberson 2022-4-14
When you do not post actual code, then we cannot give you actual answers.
For the code that you posted the bug is that Ktts1l is not defined.
Chaudhary P Patel
Chaudhary P Patel 2022-4-15
@Walter Roberson sir, just tell me is it correct? if wrong please correct me.
utdelt=([1;2;3;4;5;6;7;8;9;10;11;12;13;14;15]);
nodof=3;
for i=1
for n=1:1:5
if n==1
Utdelt=([zeros(nodof,1); (utdelt(1:nodof,i))]);
eval(['Utdelt',num2str(n),'=[zeros(nodof,1); (utdelt(1:nodof,i))]']);
else
Utdelt=utdelt([(1+(n-2)*nodof):(6+(n-2)*nodof),(i)]);
eval(['Utdelt',num2str(n),'=[utdelt([(1+(n-2)*nodof):(6+(n-2)*nodof,(i)])]']);
end
end

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

产品


版本

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by