Same loop have different vector output

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Chaudhary P Patel 2022-4-13

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1695390-same-loop-have-different-vector-output

评论： Chaudhary P Patel 2022-4-15

Sir, when i am running this loop for f_s the first f_s1 is comming as a column vector while f_s2, 3, 4, 5, are comming as a row vector.

Please sir, suggest me where i amking the mistakes.

utdelt=([1;2;3;4;5;6;7;8;9;10;11;12;13;14;15]);
Ktts=rand(6,6);
for i=1:1:10
    for n=1:1:5
        if n==1
            Utdelt=([zeros(3,1); (utdelt(1:3,i))]); 
            eval(['Utdelt',num2str(n),'=[zeros(3,1); (utdelt(1:3,i))]']);
        else
            Utdelt=utdelt([((1+(n-2)*3):(6+(n-2)*3)),i]);
            eval(['Utdelt',num2str(n),'=[utdelt((1+(n-2)*3):(6+(n-2)*3,i)]']);
        end   
        eval(['Ktts',num2str(n),'l']);
        eval(['f_s',num2str(n),'=Ktts*Utdelt']);
    end
end

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Chaudhary P Patel 2022-4-13

@Walter Roberson sir, detailed problem it is there.

sir, problem is coming in this line, because f_s2, 3, 4,5 is coming as a row vector and the Utdelt value also not taking properly. So suggest me about this line.

eval(['f_s',num2str(n),'=Ktts*Utdelt']);

Stephen23 2022-4-13

编辑：Stephen23 2022-4-13

"Please sir, suggest me where i amking the mistakes."

The obvious mistake is that you are forcing meta-data into variable names.

That forces you into writing slow, complex, inefficient, obfuscated, buggy code that is hard to debug (which is exactly what your question demonstrates, and hopefully you are about to start to notice).

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