Using a condition for two string comparison (strcmp)

16 次查看（过去 30 天）
Ana Carolina Vallone Orlandin
评论： Voss 2022-4-14
Hello!
This is my first week using matlab. I was given an assignment in which I have to use strcmp to compare two different columns for two matching elements (for example, if one contains A, the other has to contain A as well, then I know I get a logical 1 in return.). However, I also need a third column to be true, while this logical 1 is bein computed. So I need for when columns "stimulus" and "response" have the same element, that this is only going to be computed as a match if the word 'Sequence' is present in column "condition". I have tried to add for, if and finally while loop... But none work and none retrieve me a logical. My last attempt was this the statement exist that i found online:
S1 = myTable.stimulus
S2 = myTable.response
while exist('myTable.condition', 'var') == 'Sequence'
end
isCorrect = strcmp(S1, S2)
However, it does not work...
I asked the teacher and he keeps challenging me to google for finding the answer. I have not found anything that helps. The problem is that I am not familiar with many commands yet (he only exaplained how to use these statemnets for running loops, which I believe I don't need in this case).
I would appreciate any ideas on how to use strcmp with a condition when a third variable plays an important role over the data selection.

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回答（1 个）

Voss
Voss 2022-4-14
编辑：Voss 2022-4-14
Ran in:
stimulus = {'A'; 'C'; 'A'; 'B'};
response = {'A'; 'C'; 'B'; 'A'};
condition = {'not Sequence'; 'Sequence'; 'Sequence'; 'not Sequence'};
t = table(stimulus,response,condition)
t = 4×3 table
stimulus response condition ________ ________ ________________ {'A'} {'A'} {'not Sequence'} {'C'} {'C'} {'Sequence' } {'A'} {'B'} {'Sequence' } {'B'} {'A'} {'not Sequence'}
isCorrect = strcmp(t.stimulus,t.response) & strcmp(t.condition,'Sequence')
isCorrect = 4×1 logical array
0 1 0 0
  2 个评论
Ana Carolina Vallone Orlandin
Ana Carolina Vallone Orlandin 2022-4-14
Thank you! I thought that the & command had to be used with two && when i tried that :D
Voss
Voss 2022-4-14
You're welcome!
&& is for scalars only. Since the code here is dealing with vectors (i.e., each column of the table is a vector with multiple elements), we have to use &, and the result is also a vector.

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