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Concatenate fields of a structure

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Ferdi
Ferdi 2022-4-14
评论： Ferdi 2022-4-15
Hi,
I have a structure inside an app:
app.C1 struct with fields:
DHO: {{1×3 cell} {1×3 cell}}
DHOnw: {{1×3 cell} {1×3 cell}}
with:
app.C1.DHO{1}= {["ID1"]} {["GD1"]} {["ED1"]}
app.C1.DHO{2}= {["ID2"]} {["GD2"]} {["ED2"]}
and
app.C1.DHOnw{1}= {["IDnw1"]} {["GDnw1"]} {["EDnw1"]}
app.C1.DHOnw{2}= {["IDnw2"]} {["GDnw2"]} {["EDnw2"]}
The fieldnames DHO, DHOnw are not fixed, and in other cases I could have different ones.
I want to create a new “quantity” with all these fields concatenated, for example:
new={ ‘ID1’; ‘GD1’; ED1; ‘ID2’; ‘GD2’; ED2; ‘IDnw1’; ‘GDnw1’; EDnw1; ‘IDnw2’; ‘GDnw2’; EDnw2;};
to be then used as a single column of a table.
I tried with cellfun, but I was not able to get reasonable results: do you have some suggestions?
Thank you in advance for your help.

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采纳的回答

Stephen23
Stephen23 2022-4-14
Ran in:
Note that using a string array is much more efficient than storing scalar strings in a cell array.
app.C1.DHO = {{"ID1","GD1","ED1"},{"ID2","GD2","ED2"}};
app.C1.DHOnw = {{"IDnw1","GDnw1","EDnw1"},{"IDnw2","GDnw2","EDnw2"}};
app.C1
ans = struct with fields:
DHO: {{1×3 cell} {1×3 cell}} DHOnw: {{1×3 cell} {1×3 cell}}
tmp = struct2cell(app.C1);
tmp = vertcat(tmp{:}).';
out = horzcat(tmp{:})
out = 1×12 cell array
{["ID1"]} {["GD1"]} {["ED1"]} {["ID2"]} {["GD2"]} {["ED2"]} {["IDnw1"]} {["GDnw1"]} {["EDnw1"]} {["IDnw2"]} {["GDnw2"]} {["EDnw2"]}

更多回答（3 个）

Ferdi
Ferdi 2022-4-14
Thank you very much!
I will try to follow your suggestion and using a string array.
Ferdi
Ferdi 2022-4-15
Hi, I tried to follow your suggestion, surely not in the smartest way.
I recover the various function (DHO and so on) in this way (I keep the coding simple here):
function DHOSpinnerValueChanging(app, event)
app.nDHO = event.Value; % numers of DHOs
if app.nDHO ~= 0
app.PD = zeros(3*app.nDHO,1);
par0=[1,0.5,2]; %initialize some parameters
for ii=1:app.nDHO
app.PD(3*ii-2:3*ii)=ii*par0;
app.C1.DHO{ii}={"ID"+ii, "GD"+ii, "ED"+ii}; % scalar strings
app.T1.DHO(ii,:)=["ID"+ii "GD"+ii "ED"+ii]; % alternative: string array
end
end
and similarly for DHOnw.
You showed me how to treat app.C1.
To obtain a similar results witht he string array, I wrote a multiple loop:
A=string([]);
cf = cellfun(@(x) app.T1.(x), F, 'UniformOutput', false);
for j=1:numel(fieldnames(app.T1))
for k=1:height(cf{j})
for l=1:width(cf{j})
A=[A, cf{j}(k,l)];
end
end
end
A =
1×10 string array
"IL1" "GL1" "IL2" "GL2" "ID1" "GD1" "ED1" "ID2" "GD2" "ED2"
Ferdi
Ferdi 2022-4-15
Hi again, I have a comment about your first answer.
It is working only when the fields have the same dimensions.
In case like:
app.C1 struct with fields:
Lrz: {{1×2 cell}}
DHO: {{1×3 cell} {1×3 cell}}
vertcat is not working anymore.
Is there a way to make it working in this more general case?
thanks!
  2 个评论
Stephen23
Stephen23 2022-4-15
Ran in:
"Is there a way to make it working in this more general case?"
Probably, once you specify the order that should be used for said "general case". The only reason I used VERTCAT was to provide the same order that you specified in your question. If the order is not significant, then you could use HORZCAT instead:
app.C1.Lrz = {{"One","Two"}};
app.C1.DHOnw = {{"IDnw1","GDnw1","EDnw1"},{"IDnw2","GDnw2","EDnw2"}};
app.C1
ans = struct with fields:
Lrz: {{1×2 cell}} DHOnw: {{1×3 cell} {1×3 cell}}
tmp = struct2cell(app.C1);
tmp = horzcat(tmp{:});
out = horzcat(tmp{:})
out = 1×8 cell array
{["One"]} {["Two"]} {["IDnw1"]} {["GDnw1"]} {["EDnw1"]} {["IDnw2"]} {["GDnw2"]} {["EDnw2"]}
Ferdi
Ferdi 2022-4-15
thanks again, I should have found by myself.... sorry.
For general case I meant a variable number of functions.
I do not understand your reference to the order as it seems however preserved.
thanks

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