I keep getting not enough input arguments error when trying to make a sine function
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function [x,t] = sin_NU(fs,f0,T)
t = 0:1/fs:T; %time vector
x = sin(2*pi*f0*t); %signal vector
end
I am trying to make a sine function and sample the sine signal with a certain sampling frequency. Please help, I would really appreciate it!
5 个评论
Dyuman Joshi
2022-4-14
编辑：Dyuman Joshi
2022-4-14
How are you calling your function? Show the error as well.
Use .* if f0 is not a scalar
kiroro00
2022-4-14
Jamal Badiee
2022-4-14
I ran your code by just copy pasting and got no error.
kiroro00
2022-4-14
Works fine, @kiroro00
[x,t] = sin_NU(1000,10,0.5);
figure(1);
plot(t,x);
xlabel ('Time');
ylabel ('Signal');
title ('sin NU function test');
function [x,t] = sin_NU(fs,f0,T)
t = 0:1/fs:T; %time vector
x = sin(2*pi*f0*t); %signal vector
end
采纳的回答
It's possible that you inadvertently clicked the run button or hit the F5 key in the MATLAB editor window where sin_NU.m was open, which ran the function sin_NU with no input arguments. When that happens, you get the error "Not enough input arguments" on the first line where an input argument is used.
When you run sin_NU with input arguments, as in:
[x,t] = sin_NU(1000,10,0.5);
no error happens because the input arguments are given.
And if you want to see a discrete signal, you may consider using stem instead of plot:
[x,t] = sin_NU(1000,10,0.5);
figure(1);
stem(t,x);
xlim([0 0.06]); % zoom in to show the stems
xlabel ('Time');
ylabel ('Signal');
title ('sin NU function test');
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