gamma function error in calculation

2 次查看(过去 30 天)
% Starting value
The above formula is coded as follows:
syms x a
Y=sym(zeros(1));
Y(1)=0;
a=1/2
for i=1:4
if i==5
A=1
else
A=0
end
if i==4
B=1
else
B=0
end
Y(i+1)=simplify((gamma(a*(i-1)+1)/gamma((a*(i-1)+3/2))*(A-Y(i)+((2*B)/gamma(5/2)))));
end
disp(Y)
But it is showing the calculation error Y(5)=1 but the value is shown in MATLAB is as follows:('2535301200456458897054207582575/2535301200456458802993406410752'). Ecxept Y(5) all values are zeros

回答(1 个)

VBBV
VBBV 2022-4-16
syms x a
Y=sym(zeros(1));
Y(1)=0;
a=1/2
a = 0.5000
for i=1:4
if i==5
A=1;
B = 0;
Y(i+1)=simplify((gamma(a*(i-1)+1)/gamma((a*(i-1)+3/2))*(A-Y(i)+((2*B)/gamma(5/2)))));
else
A=0;
B =1 ;
Y(i+1)=simplify((gamma(a*(i-1)+1)/gamma((a*(i-1)+3/2))*(A-Y(i)+((2*B)/gamma(5/2)))));
end
if i==4
B=1;
A = 0;
Y(i+1)=simplify((gamma(a*(i-1)+1)/gamma((a*(i-1)+3/2))*(A-Y(i)+((2*B)/gamma(5/2)))));
else
B=0;
A = 1;
Y(i+1)=simplify((gamma(a*(i-1)+1)/gamma((a*(i-1)+3/2))*(A-Y(i)+((2*B)/gamma(5/2)))));
end
end
A = 0
B = 0
A = 1
A = 0
B = 0
A = 1
A = 0
B = 0
A = 1
A = 0
B = 1
disp(vpa(Y,4))
  3 个评论
yogeshwari patel
yogeshwari patel 2022-4-17
The correct value are Y(1)=0; Y(2)=0;Y(3)=0, Y(4)=0, Y(5)=1 and rest value s are zero. Now if I work with pen and paper the values are same as I mention above but when I work with MATLAB code the value of Y(5)=2535301200456458897054207582575/2535301200456458802993406410752 .Why that error is appaering
Torsten
Torsten 2022-4-17
You mix symbolic and floating point parameters in the calculation of Y(5). This will result in reduced accuracy.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Calculus 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by