loop of Column Average

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Arvind Gauns
Arvind Gauns 2022-4-19
评论： Arvind Gauns 2022-4-19
I have a matrix of 1024 * 78.(datatype: double )
I want to average every two columns such that the resultant matrix must be 1024*39. (average of every two matrix)
how to get it done?
again for time being if i dont know the number of columns (due to huge dataset) and want to run a loop for averaging the columns for the similar case as mentioned about, what will be the changes in the code ?

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采纳的回答

Davide Masiello
Davide Masiello 2022-4-19
编辑：Davide Masiello 2022-4-19
Ran in:
There's no need to use a for loop.
Try the code below.
clear,clc
A = rand(1024,78); % initial matrix of doubles
B = (A(:,1:2:end-1)+A(:,2:2:end))/2; % matrix of averages for each two columns
size(B)
ans = 1×2
1024 39

更多回答（1 个）

Eric Delgado
Eric Delgado 2022-4-19
Hi @Arvind Gauns, just pass your input matrix to the function below. Hope it helps! :)
function outMatrix = Fcn_twoColumnsMean(inMatrix)
arguments
inMatrix (1024,:) {mustBeNumeric} = randn(1024, 78)
end
NN = floor(width(inMatrix)/2);
outMatrix = zeros(1024, NN);
for ii = 1:NN
outMatrix(:,ii) = mean(inMatrix(:,2*ii-1:2*ii), 2);
end
end
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Eric Delgado
Eric Delgado 2022-4-19
For sure! Especially if the script is becoming too big. So... you have to create modules for debugging purposes. But at the end of the day, it's your call! :)
Arvind Gauns
Arvind Gauns 2022-4-19
in that case i need not need to call the function right ?

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