Calculating u and v components from wind direction and speed
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Hi,
I would like to plot a wind filed on a map.
I have lat vector, lon vector, wind speed vector and wind direction vector.
As far as I understand the simplest way is to use quiverm or quiver (but quiver can't plot over a map).
To use both function I need the u and v components, and I don't have them, and I don't have the angle for the cos and sin functions in these formulas.
How can calculate them? converting wind direction to math degrees (in a formula) isn't straight forward.
Appricate your help for the easiest way.
Thank you!
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Les Beckham
2022-4-19
编辑:Les Beckham
2022-4-19
Actually, it is straightforward.
v (North (y) component) and u (East (x) component) can be calculated from S (wind speed) and D (direction) as follows
S = 10; % example - replace with your data
D = 30; % example, wind coming from the North-northeast
D = 270 - D; % convert wind direction to Matlab graphics coordinate convention
u = S*cosd(D);
v = S*sind(D);
quiver(0,0,u,v)
axis equal
xlim([-10 10])
ylim([-10 10])
grid on
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Les Beckham
2022-4-22
You are welcome.
Would you mind accepting the answer then?
Unfortunately, I don't have the mapping toolbox so I'm not going to be much help with that. Looking at the online doc, though, it looks pretty similar to quiver. You will probably need to play around with the scale argument to quiverm (using this syntax: h = quiverm(lat,lon,deltalat,deltalon,scale)) to use your u and v speed components as the deltalat and deltalon arguments.
Good luck.
更多回答(3 个)
Tala
2022-4-19
编辑:Tala
2022-4-19
I have done similar tasks before. If you have experimental data, your sensor should generate two time histories; velocity (Mag) and direction (Dir) with identical length, depending on your smapling frequency. To th ebest of knowledge, no sensor can read in 3D, you need to rotate your sensor if you want Z direction measurments.
You are right, direction could be tricky because small changes in wind direction could cause significant changes in the probe's reading. In other words, your probe could read between 350 and 10 degrees but in reallity these are all similar values. You need to be strategic about placing your probe at the right angle. If you avarage it out you get 180, completely opposite angle! The graph below shoes the issue:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/969505/image.jpeg)
I could not find the code that I used before, but I did something like this:
% truncating the first and last few data points
%nn= number of points you wanna truncate from the beginning
%mm= number of points you wanna truncate from the end
Vx=sum((Mag(nn:mm)).*cosd((Dir(nn:mm))))/(mm-nn+1); %V(i).cos(theta(i))/n
Vy=sum((Mag(nn:mm)).*sind((Dir(nn:mm))))/(mm-nn+1);
angle=atand(Vy/Vx);
% now you need to create a x y z domain (in your case lat lon height)
% Vz=0 in this case
quiver3(x,y,z,Vx,Vy,0);
Below is the plot I got from my experiments back in the day. I measured the wiind speed around buildings at 3 different heights.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/969475/image.jpeg)
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BHUKYA SAMA
2023-9-17
i have matrix V(lat,lon,level,time) how to do dV/dZ, can i use gradient (V)/gradient (Z) ?
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BHUKYA SAMA
2023-9-17
编辑:KSSV
2024-7-11
i am need to ccalculate the dV/dZ from era5, below code is okay?
clear all
close all
fclose all
load era5_all_level_parametrs_2015_04_04.mat
%%%%%%%% Hlecity %%%%%%%%%55
u_wind_avg=0.5*(u1(1,1,26,1)-u1(1,1,37,1));%u(lon,lat,level,time)
v_wind_avg=0.5*(v1(1,1,26,1)-v1(1,1,37,1));%v(lon,lat,level,time)
for i=1:37
p0=1000;
ht(i)=8*log(level1(i)/p0);
end
ht1=-ht;
ht2=ht1*1000;
% du_dz=gradient(u1(:,:,26:end,:))/(ht2(26)-ht2(end));
% dv_dz=gradient(v1(:,:,26:end,:))/(ht2(26)-ht2(end));
du_dz=gradient(u1(1,1:2,26:end,1));
dv_dz=gradient(v1(1,1,26:end,1));
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