Info

此问题已关闭。 请重新打开它进行编辑或回答。

Error in a matlab function

2 次查看（过去 30 天）
Elena
Elena 2015-1-15
关闭： MATLAB Answer Bot 2021-8-20
Hello. i have a problem of dimension in this function:
function Generalized_coefficient= loggfc(alpha,n)
for m=1:1:n-1
f=[2:1:m-1];
g=[1:1:m-1];
x=[1:1:m+1];
Generalized_coefficient =logalpha;
a= log(m-alpha*f)+ Generalized_coefficient(f);
b=logalpha +Generalized_coefficient(g);
themax= max(a,b);
x(1)=log(m-alpha*1)+ Generalized_coefficient(1);
x(f)=themax+ log(exp(a-themax)+ exp(b-themax));
x(m+1)=logalpha+ Generalized_coefficient(m);
Generalized_coefficient=x;
end
end
When i put n=2; it's ok but when i set n=3 matlab provide me this error
"Attempted to access Generalized_coefficient(2); index out of bounds because numel(Generalized_coefficient)=1" How can i correct the code? Thank you
  6 个评论
显示 4更早的评论
Elena
Elena 2015-1-15
Thank you for your explanation. The problem is that i don't know how to modify numel(), in order for cicle goes on..
dpb
dpb 2015-1-15
You can't "modify" numel; it's the size of the array in the argument. Only changing that size/length of the array to be as long as the largest index or restricting the address to be within the actual length will cure the problem.
The difficulty is as described that it's not at all clear what your function is supposed to be doing since all we have is nonworking code; no description of what an expected output would be given an input.

请先登录，再回答此问题。

回答（1 个）

Image Analyst
Image Analyst 2015-1-15
"logalpha" is not defined. Perhaps you meant log(alpha).
Then, for n=2, m goes from 1 to 1, you say
f=[2:1:0]; % This will be empty.
a= log(m-alpha*f)+ Generalized_coefficient(f); % Kaboom!
so that will bomb - not sure why you said it doesn't.
Then, for n=2, m goes from 1 to 2, you say
f=[2:1:2]; % This will be 2.
a= log(m-alpha*f)+ Generalized_coefficient(f); % Kaboom!
Well, Generalized_coefficient does not have two elements yet. Luckily there is a way to solve this, and here it is.

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by