Split an Array in sub-arrays based on the first number in the column

Question

Fabio Taccaliti 2022-4-19

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1700120-split-an-array-in-sub-arrays-based-on-the-first-number-in-the-column

评论： Stephen23 2022-4-20

Hello,

I have an array M 2939x4 that I would like to split in sub-arrays based on the number in the first column.

I mean in the first colunm a number is listed, first 0, then 0.02, then 0.04 and so on (with an increment of 0.02) until 2.2, the problem is that the times that this number appear is not always the same (for example the 0 is on the first 28 rows, the 0.02 in the following 24 and the 0.04 in the next 29).

My idea was to find the number of different number listed in the first column (time) and how many times they occurs (b).

[time,b] = unique(M(:,1));

b = [b; length(M)];

How can I continue it?

Thanks in advance.

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Answer 1

Stephen23 2022-4-19

1
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1700120-split-an-array-in-sub-arrays-based-on-the-first-number-in-the-column#answer_946065

在 MATLAB Online 中打开

M = [[0;0.2;0.2;0.4;0.6;0.6;0.6],rand(7,3)]
M = 7×4
         0    0.4950    0.3418    0.1799
    0.2000    0.7419    0.8047    0.6176
    0.2000    0.0316    0.7905    0.7259
    0.4000    0.0520    0.9471    0.8603
    0.6000    0.2431    0.9200    0.8624
    0.6000    0.2946    0.9786    0.6720
    0.6000    0.1605    0.0039    0.7209
D = diff(find([1;diff(M(:,1));1]));
C = mat2cell(M,D,4)
C = 4×1 cell array
    {[     0 0.4950 0.3418 0.1799]}
    {2×4 double                   }
    {[0.4000 0.0520 0.9471 0.8603]}
    {3×4 double                   }
C{:}
ans = 1×4
         0    0.4950    0.3418    0.1799
ans = 2×4
    0.2000    0.7419    0.8047    0.6176
    0.2000    0.0316    0.7905    0.7259
ans = 1×4
    0.4000    0.0520    0.9471    0.8603
ans = 3×4
    0.6000    0.2431    0.9200    0.8624
    0.6000    0.2946    0.9786    0.6720
    0.6000    0.1605    0.0039    0.7209