Using a user defined fucntion with blockproc

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Jason
Jason 2015-1-15
评论： Jason 2015-1-15
Is there a mistake in my syntax using blocproc:
Binary1=blockproc(OrigImage,[tileRowSize, tileColSize],@(x) myOperation(hObject, eventdata, handles, x.data));
the function I use "myOperation" is as follows:
function myOperation(hObject, eventdata, handles,tile)
[thresh1, thresh2] = Threshold(hObject, eventdata, handles,tile); %my personal thresholding function
%Create Binary Image
size(tile)
ix=tile;
level=thresh2
ix(ix<level)=0;
ix(ix>level+1)=1;
Im getting
Binary1 =
[]

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回答（2 个）

Image Analyst
Image Analyst 2015-1-15
I don't have time to look at it now, but in the meantime, see my blockproc demos, attached.
Iain
Iain 2015-1-15
What does your "myfunction" function output? It looks like it's not producing any output.
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Image Analyst
Image Analyst 2015-1-15
If you have blocks of 25 pixels by 25 pixels, and you move in "jumps" of 25 pixels, then I believe your last block will have only 1 row or column. Thus it may not have a value like the others that had a full block in them.
Jason
Jason 2015-1-15
Yes that makes sense.
Is it possible to return also the mean intensity of each sub image using blockproc, I thought I could just add an extra output variable from my function such as:
function [BI, mn] = myOperation(hObject, eventdata, handles,tile)
mn=mean(tile)
%then the rest of the code.
and then obtain a matrix of mean values via:
[Binary1, mn]=blockproc(OrigImage,[tileRowSize, tileColSize],@(x) myOperation(hObject, eventdata, handles, x.data));
But it complains about too many output arguments for Blockproc.

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