Why this piece of code gives error?
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CostFunction='fun4sn0';
nPop=120;
nVar=4;%nVar=1000;
nPop_Initial=nPop;
nPop_Final=30;
MaxNFE=3e3;
MaxIter0=ceil(MaxNFE/((nPop_Initial+nPop_Final)/2)); % Approximate Maximum Iterations
Cr=0.5;
xmin=[0 0 0 0];
xmax=[10 10 pi pi];
%%%%%%%%%%%
NFE=0;
Gbest.Position=[];
Gbest.Cost=inf;
BestCosts=nan(1,MaxIter0);
nfe=BestCosts;
for i=1:nPop
Velocity(i,:)=zeros(1,nVar); %#ok<*SAGROW>
Position(i,:)=xmin+(xmax-xmin).*rand(1,nVar);
Cost(i)=CostFunction(Position(i,:));
PbestPosition(i,:)=Position(i,:);
PbestCost(i)=Cost(i);
PbestVel(i,:)=Velocity(i,:);
if PbestCost(i)<Gbest.Cost
Gbest.Position=PbestPosition(i,:);
Gbest.Cost=PbestCost(i);
Gbest.Velocity= PbestVel(i,:);
end
end
2 个评论
采纳的回答
Steven Lord
2022-4-20
Either make your CostFunction variable a function handle to the fun4sn0 function (which is the approach I'd prefer):
CostFunction= @fun4sn0;
or use feval to evaluate the function by name.
Cost(i) = feval(CostFunction, Position(i, :));
Both of these assume that your function returns a scalar, since you're assigning its output into one element of the Cost variable.
3 个评论
Image Analyst
2022-4-21
@Steven Lord messing with function handles and feval() seems like a roundabout way to do it. Is that better than just calling the function directly like I suggested?
Cost(i) = fun4sn0(Position(i,:));
Steven Lord
2022-4-21
@Image Analyst That is another option, and is the easiest if you want to hard-code the cost function. I think that particular name put me in "this is likely going to be used in some form of optimization" mode and in that case (the "function function" scenario, see ode45, fminsearch, fzero, integral, etc.) to keep the code as a general purpose solver you wouldn't want to hard-code the function.
更多回答(1 个)
Image Analyst
2022-4-20
CostFunction is a character array, not an actual function. Did you mean
Cost(i) = fun4sn0(Position(i,:));
instead of
Cost(i)=CostFunction(Position(i,:));
Thorough discussion of the error in the FAQ:
另请参阅
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