Create a long rectangular signal with a function handle

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AEW
AEW 2022-4-20
编辑： AEW 2022-4-20
I was wondering if there is a quick way to create a rectangular signal during 20 sec for example, with a function handle. I tried the following command which requires you to do it for every step.
Thanks.
u=@(t) double((0<=t & t<0.5) + ...
(1<=t & t<1.5) + ...
(2<=t & t<2.5)) .* 1;

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采纳的回答

Bruno Luong
Bruno Luong 2022-4-20
编辑：Bruno Luong 2022-4-20
Ran in:
myfun = @(t) mod(t,1)<=0.5;
ezplot(myfun, 0, 20)
  4 个评论
显示 2更早的评论
Bruno Luong
Bruno Luong 2022-4-20
Ran in:
fun=@(x) ppval(mkpp(0:0.25:1,[1; 0; -1; 0]),mod(x,1))
fun = function_handle with value:
@(x)ppval(mkpp(0:0.25:1,[1;0;-1;0]),mod(x,1))
ezplot(fun,0,3)

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更多回答（1 个）

Sam Chak
Sam Chak 2022-4-20
@AEW
Second opinion!
fcn = @(t) (sign(sin(2*pi*t)) + 1)/2;
ezplot(fcn, 0, 5)

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