How to slice an array across multiple dimensions with two limit arrays?

Question

Brian Kardon 2022-4-22

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1702750-how-to-slice-an-array-across-multiple-dimensions-with-two-limit-arrays

编辑： Bruno Luong 2022-4-22

I'm interested in taking an arbitrary N-dimensional array, and two 1xN vectors, and using the two vectors as start/stop indices to slice the array, but I'm not sure how. Here's what I mean:

Let X be an N-dimensional array.

Let A and B be 1xN vectors like so:

A=[a1, a2, ..., aN]

B=[b1, b2, ..., bN]

How do I slice X such that I get this:

Y = X(a1:b1, a2:b2, ..., aN:bN)

I tried X(A:B), but that doesn't work - not even sure what that operation is doing, but it isn't doing what I want. I tried to think of some way to do it with logical indexing, but nothing simple came to mind. I could slice the array one dimension at a time in a loop, but it seems like there must be a one-liner. Thanks!

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Answer 1

Bruno Luong 2022-4-22

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https://ww2.mathworks.cn/matlabcentral/answers/1702750-how-to-slice-an-array-across-multiple-dimensions-with-two-limit-arrays#answer_948550

编辑：Bruno Luong 2022-4-22

在 MATLAB Online 中打开

This should work

X=rand(6,6,6);
A=[1 2 3]; B=[6 5 4];
cidx = arrayfun(@(i1,i2) i1:i2, A, B, 'unif', 0);
Y = X(cidx{:})
Y = 
Y(:,:,1) =

    0.7739    0.3475    0.5936    0.5165
    0.5514    0.0120    0.8295    0.7020
    0.7219    0.0188    0.0139    0.2095
    0.6081    0.2888    0.2122    0.9462
    0.7840    0.4617    0.7677    0.1717
    0.3399    0.1233    0.8264    0.1021


Y(:,:,2) =

    0.8648    0.4441    0.7968    0.1729
    0.2677    0.8310    0.6914    0.3000
    0.7044    0.0935    0.5411    0.2597
    0.1844    0.8915    0.9166    0.0287
    0.8937    0.8579    0.5319    0.6198
    0.1937    0.8000    0.0968    0.2708