Read a Special Text File

I was wondering if there is a quick way to read the following text file sample where the first data line starts with a bracket. I would like to avoid the hassle of manually removing the bracket from every file I obtain. I use the following command for now after I remove the bracket.
Thanks.
data = textscan(Fopen, '%d %f %d %d %d;', 'HeaderLines',2)
file.txt

1 个评论

A simple and very efficient approach would be to simply define the square bracket as whitespace, which you can do using TEXTSCAN's WHITESPACE option. Another good approach would be to use a fixed-width import via READTABLE.
Using STR2NUM is not very efficient.

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 采纳的回答

Here are two much more efficient approaches.
The first is exactly like you are doing now, just adding the WHITESPACE option to efficiently ignore the square bracket:
fnm = 'textfile.txt';
fmt = '%d%f%d%d%d;';
opt = {'HeaderLines',2, 'Whitespace',' \t['};
fid = fopen(fnm,'rt');
data = textscan(fid, fmt, opt{:})
data = 1×5 cell array
{11130×1 int32} {11130×1 double} {11130×1 int32} {11130×1 int32} {11130×1 int32}
fclose(fid);
The second is to import the file as table, which has headers and may be more convenient to access:
opt = detectImportOptions(fnm, 'FileType','fixedwidth', ...
'VariableWidths',[6,9,16,16,16], 'VariableNamesLine',1, ...
'VariableNamingRule','preserve', 'Range',3, 'Whitespace',' [', ...
'ExtraColumnsRule','ignore');
tbl = readtable(fnm,opt)
tbl = 11130×5 table
Sample Time Commanded Pos Encoder 1 Pos Encoder 2 Pos ______ _____ _____________ _____________ _____________ 0 0 0 0 0 1 0.001 0 0 0 2 0.002 0 0 0 3 0.003 0 1 0 4 0.004 0 4 0 5 0.004 0 7 0 6 0.005 0 14 0 7 0.006 0 20 0 8 0.007 0 27 0 9 0.008 0 37 0 10 0.009 0 47 0 11 0.01 0 57 1 12 0.011 0 66 3 13 0.012 0 76 4 14 0.012 0 87 6 15 0.013 0 98 7

更多回答(2 个)

Voss
Voss 2022-4-22
编辑:Voss 2022-4-22
% read file into character vector data
data = fileread('textfile.txt');
% remove the first two lines
idx = find(data == newline(),2);
data(1:idx(end)) = [];
% convert to numeric
M = str2num(data);
% show some results
format long
disp(M(1:10,:));
0 0 0 0 0 1.000000000000000 0.001000000000000 0 0 0 2.000000000000000 0.002000000000000 0 0 0 3.000000000000000 0.003000000000000 0 1.000000000000000 0 4.000000000000000 0.004000000000000 0 4.000000000000000 0 5.000000000000000 0.004000000000000 0 7.000000000000000 0 6.000000000000000 0.005000000000000 0 14.000000000000000 0 7.000000000000000 0.006000000000000 0 20.000000000000000 0 8.000000000000000 0.007000000000000 0 27.000000000000000 0 9.000000000000000 0.008000000000000 0 37.000000000000000 0
disp(M(end-9:end,:));
1.0e+05 * 0.111200000000000 0.000098460000000 0 1.003280000000000 0.222970000000000 0.111210000000000 0.000098470000000 0 1.002280000000000 0.222750000000000 0.111220000000000 0.000098480000000 0 1.001270000000000 0.222530000000000 0.111230000000000 0.000098480000000 0 1.000280000000000 0.222310000000000 0.111240000000000 0.000098490000000 0 0.999280000000000 0.222090000000000 0.111250000000000 0.000098500000000 0 0.998290000000000 0.221870000000000 0.111260000000000 0.000098510000000 0 0.997310000000000 0.221640000000000 0.111270000000000 0.000098520000000 0 0.996330000000000 0.221420000000000 0.111280000000000 0.000098530000000 0 0.995360000000000 0.221190000000000 0.111290000000000 0.000098540000000 0 0.994390000000000 0.220970000000000
r=readmatrix('file.txt');%see if this will work

3 个评论

Thank you for the answer.
Unfortunately, it does not work. I get the following:
If you attach the text file, I would be able to help better.
Please find it attached.
Thanks.

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