Computing Double integrals with ymax

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Ikenna Iwudike
Ikenna Iwudike 2022-4-22
回答： Torsten 2022-4-22
F = @(x,y) y*sqrt(x.^2 - y.^2);
ymax = @(x)x;
q = integral2(F,1,2,0,ymax)
I need help with computing this double integral. my bounds for y are 0 and x, but it won't work even when I make ymax a function handle.

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采纳的回答

Torsten
Torsten 2022-4-22
F = @(x,y) y.*sqrt(x.^2 - y.^2);
instead of
F = @(x,y) y*sqrt(x.^2 - y.^2);

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