Double Integral using ymax and ymin

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Ikenna Iwudike
Ikenna Iwudike 2022-4-22
回答： Star Strider 2022-4-22
I'm having trouble trying to integrate this function. My y bounds are ln(x)/x to 1/x. my x bounds are 1 to e.
F = @(x,y)exp(x*y);
ymin = @(x)log(x)/x;
ymax = @(x)1/x;
q = integral2(F,1,exp,ymin,ymax)

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Star Strider
Star Strider 2022-4-22
Ran in:
Use element-wise operations for the multiplications and divisions in the anonymous functions. Also exp must have an argument.
Try this —
F = @(x,y)exp(x.*y);
ymin = @(x)log(x)./x;
ymax = @(x)1./x;
q = integral2(F,1,exp(1),ymin,ymax)
q = 1.0000
Make appropriate changes to get the desired result.
.

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