ordinary differential equation

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12ar.af 2011-9-29

i have an equation d(theta)/dt=((P*L^2)/(E*I))*sin(theta*D/L)

L=55.863; D=15.484; E=200*10^9; I=138; P=440*10^6

The initial theta at 1198 years is 0.010degrees.

i have to find theta from the year 1198 to 1990

can someone please help me.its urgent

Grzegorz Knor 2011-9-29

Use ode45:

L=55.863; D=15.484; E=200*10^9; I=138; P=440*10^6;
ode45(@(t,theta)((P*L^2)/(E*I))*sin(theta*D/L),[1198 1990],0.01)

12ar.af 2011-9-29

Can we make the values into a table or something.like year and theta side by side?

Grzegorz Knor 2011-9-29

Yes, read one of my comment above.

[T THETA] = ode45(@(t,theta)((P*L^2)/(E*I))*sin(theta*D/L),[1198:1990],0.01);

disp([T THETA])

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