Failure in initial objective function evaluation. FSOLVE cannot continue.

Question

ma xueyi 2022-4-25

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1704770-failure-in-initial-objective-function-evaluation-fsolve-cannot-continue

回答： ma xueyi 2022-4-30

采纳的回答： Jan

在 MATLAB Online 中打开

i set two files as main.m and root.m.

Here are my codes.

When I runs main.m,it keeps telling me that "Failure in initial objective function evaluation. FSOLVE cannot continue."

Hope someone can help me with that.Thanks!

[main.m]
clear all; clc
fun = @root;
x0 = [2e-5,0.04,0.1524,1.0194,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0];
x = fsolve(fun,x0)
[root.m]
global Tinlet Treact T0
Tinlet = 273+25  ;%K
Treact = 273+150  ;%K
T0 = 273+25;%K
global ki1 ki2 kp11 kp12 kp21 kp22 ktal kd    ki10  kp110 kp120 kp210 kp220 ktal0 kd0     Eki1  Ekp11 Ekp12 Ekp21 Ekp22 Ektal Ekd  R
R = 8.314;
ki10 = 13.0;
Eki1 = 10000;
ki1 = ki10 * exp(-Eki1*(1/Treact-1/T0));
ki2 = 0.0;
kp110 = 3.70e+05;
Ekp11 = 10000;
kp11 = kp110 * exp(-Ekp11*(1/Treact-1/T0));
kp120 = 673;
Ekp12 = 10000;
kp12 = kp120 * exp(-Ekp12*(1/Treact-1/T0));
kp210 = 1.36e+03;
Ekp21 = 10000;
kp21 = kp210 * exp(-Ekp21*(1/Treact-1/T0));
kp220 = 46 ;
Ekp22 = 10000;
kp22 = kp220 * exp(-Ekp22*(1/Treact-1/T0));
ktal0 = 2.5;
Ektal = 10000;
ktal = ktal0 * exp(-Ektal*(1/Treact-1/T0));
kd0 = 1.0e-04;
Ekd = 10000;
kd = kd0 * exp(-Ekd*(1/Treact-1/T0));
function F = fun(x)
    F(1) =ktx(2)*x(5)+x(6)*x(2)-ki1*x(1)*x(3)-ki2*x(1)*x(4)-x(14);
    F(2) =UDSI0 - x(14)*stoptime-x(1);
    F(3) =ktx(2)*x(2)*(x(6)+x(7))-x(15);
    F(4) =UDSI1 - x(15)*stoptime-x(2);
    F(5) =(ki1*x(1)+kp11*x(5)+kp21*x(6))*x(3)-x(16);
    F(6) =UDSI2 - x(16)*stoptime-x(3);
    F(7) =(ki2*x(1)+kp12*x(5)+kp22*x(6))*x(4)-x(17);
    F(8) =UDSI3 - x(17)*stoptime-x(4);
    F(9) =ki1*x(1)*x(3)+kp21*x(6)*x(3)-kp12*x(5)*x(4)-(ktx(2)*x(2)+kd)*x(5)-x(18);
    F(10) =UDSI4 - x(18)*stoptime-x(5);
    F(11) =ki2*x(1)*x(4)+kp12*x(5)*x(4)-kp21*x(6)*x(3)-(ktx(2)*x(2)+kd)*x(6)-x(19);
    F(12) =UDSI5 - x(19)*stoptime-x(6);
    F(13) =ki1*x(1)*x(3)+kp11*x(5)*x(3)+kp21*(x(7)+x(6))*x(3)-kp12*x(7)*x(4)-(ktx(2)*x(2)+kd)*x(7)-x(20);
    F(14) =UDSI6 - x(20)*stoptime-x(7);
    F(15) =ki2*x(1)*x(4)+kp22*x(6)*x(4)+kp12*(first_lamada2+x(5))*x(4)-kp21*x(7)*x(3)-(ktx(2)*x(2)+kd)*first_lamada2-x(21) ;
    F(16) =UDSI7 - x(21)*stoptime-x(8);
    F(17) =ki1*x(1)*x(3)+kp11*(2*x(7)+x(5))*x(3)+kp21*(x(10)+2*x(8)+x(6))*x(3)-kp12*x(9)*x(4)-(ktx(2)*x(2)+kd)*x(9)-x(22);
    F(18) =UDSI8 - x(22)*stoptime-x(9);
    F(19) =ki2*x(1)*x(4)+kp22*(2*x(8)+x(6))*x(4)+kp12*(x(9)+2*x(7)+x(5))*x(4)-kp21*x(10)*x(3)-(ktx(2)*x(2)+kd)*x(10)-x(23);
    F(20) =UDSI9 - x(23)*stoptime-x(10);
    F(21) =(ktx(2)*x(2)+kd)*(x(5)+x(6))-x(24);
    F(22) =UDSI10 - x(24)*stoptime-x(11);
    F(23) =(ktx(2)*x(2)+kd)*(x(7)+x(8))-x(25);
    F(24) =UDSI11 - x(25)*stoptime-x(12);
    F(25) =(ktx(2)*x(2)+kd)*(x(9)+x(10))-x(26);
    F(26) =UDSI12 - x(25)*stoptime-x(13);
    F = [F(1),F(2),F(3),F(4),F(5),F(6),F(7),F(8),F(9),F(10),F(11),F(12),F(13),F(14),F(15),F(16),F(17),F(18),F(19),F(20),F(21),F(22),F(23),F(24),F(25),F(26)];
end

5 个评论
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Alex Sha 2022-4-27

You haven't given those data yet.

Rik 2022-4-30

Comment posted as flag by ma xueyi:

thanks, i provided the data otherplace

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Answer 1

Jan 2022-4-27

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1704770-failure-in-initial-objective-function-evaluation-fsolve-cannot-continue#answer_952095

在 MATLAB Online 中打开

You provide a handle to a script. This cannot work, because fsolve expects a function handle. Most likely you want:

fsolve(@fcn, x0)

instead. Currently the constants are not visible in the function fcn. Maybe you want to declare the variables as globals there also? What is stoptime?

Whenever you mention an error in the forum, paste a copy of the complete error message, not just some parts of it.