How to design Spur Gear

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Swapnil Bansal
Swapnil Bansal 2022-4-26
回答： Himanshu 2024-1-8
clear
clc
H=100;
np=1120;
phin=20;
Np=18;
Ng=72;
R=0.95;
N=1000000000;
Ko=1;
nd=2;
Qv=6;
Kb=1;
Pd=4;
mb=1.2;
% diametral pitch selection
disp('DIAMETRAL PITCH SELECTION->')
dp=Np/Pd;
disp('The value of dp in inch =')
disp(dp);
dg=Ng/Pd;
disp('The value of dg in inch =')
disp(dg);
Yp=0.309;
Yg=0.4324;
Jp=0.32;
Jg=0.415;
v=(3.14*dp*np)/12;
disp('The value v in ft/min =')
disp(v);
Wt=(33000*H)/v;
disp('The value Wt in lbf =')
disp(Wt);
cons=(12-Qv)^(2/3);
B=0.25*cons;
A=50+56*(1-B);
Kv=((A+sqrt(v))/A)^(B);
Kr=0.658-(0.0759)*log(1-0.95);
Mk=(N)^(-0.8255);
Ynp=1.355*Mk;
jk=(R/Pd)^(-0.0178)
Yng=1.3558*jk;
cnk=(R)^(-0.023);
Znp=1.4488*cnk;
knk=(R/Pd)^(-0.023);
Zng=1.4488*knk;
F=(4*3.14)/Pd;
ksk=F*sqrt(Ynp);
kk=(ksk/Pd)^(0.0535);
Ks=11.22*kk;
Cmc=1;
Cpm=1;
Ce=1;
Cma=0.175;
f=(F)/(10*dp);
Cpf=f-0.0375+(0.0125*F);
Km=1+1*(Cpf*1+Cma*1);
Cp=2300;
mg=4;
mn=1;
csk=(dp)/(dp+1);
rcb=(cos(20)*sin(20))/2;
I=csk*rcb;
% pinion tooth bending
disp('PINION TOOTH BENDING-->')
hr=320;
Kt=1;
Sc=170000;
St=86.2*hr+12730;
Fb=(nd*Wt*Ko*Ks*Pd*Km*Kb*Kr)/(Jp*St*Yng);
disp('Facewidth necessary to resist bending fatigue =')
disp(Fb);
cs=(Cp*Kt*Kr)/(Sc*Znp);
jj=(cs)^(2);
Fw=(jj*nd*Wt*Ko*Kv*Ks*Km*Cpf)/(dp*I);
disp('Facewidth necessary to resist wear fatigue =')
disp(Fw);
% correcting the above values
disp('CORRECTING THE ABOVE VALUES-->')
F=3.5;
disp('Facewidth =')
disp(F);
fp=(F)/(10*dp);
pk=(F*sqrt(Yp))/Pd;
sk=(pk)^(0.0535);
Ks=1.192*sk;
Cpf=fp-0.0375+(0.0125*F);
Km=1+1*(Cpf*1+0.175*1);
disp('Value of km is =')
disp(Km);
sigmap=(2502*1*1.48*1.147*4*1.259*1)/(3.5*0.32);
disp('Bending stress induced by Wt in psi=')
disp(sigmap);
FOSp=(40310*0.938)/(1*0.885*19100);
disp('Factor of safety in bending of pinion is =')
disp(FOSp);
%gear tooth bending
disp('GEAR TOOTH BENDING-->')
sigmag=(19100*0.32)/0.415;
disp('value of sigmag =')
disp(sigmag);
FOSg=(40310*0.961)/(1*0.885*14730);
disp('Factor of safety of gear in bending =');
disp(FOSg);
% pinion tooth gear
disp('PINION TOOTH GEAR-->')
gk=sqrt((2502*1*1.48*1.147*1.259*1)/(4.5*3.5*0.129));
sigmacp=2300*gk;
disp('Value of sigmacp in psi =')
disp(sigmacp);
FOS=(170000*0.9)/(1*0.885*118000);
disp('Factor of safety =');
disp(FOS);
%pinion bending
disp('PINION BENDING-->')
kl=(FOS)^(2);
ch=1;
sigmacg=118000;
Sc=170000;
%gear tooth wear
disp('GEAR TOOTH WEAR-->')
FOSgw=(Sc*0.929)/(1*0.885*sigmacg);
disp('Factor of safety =');
disp(FOSgw);
% gear in wear
disp('GEAR IN WEAR-->')
ml=(FOSgw)^(2);
% Rim
disp('RIM-->')
ht=2.25/Pd;
disp('Whole depth in inch is =');
disp(ht);
tr=mb*ht;
disp('Thickness of rim in inch is =');
disp(tr);

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回答（1 个）

Himanshu
Himanshu 2024-1-8
Hey Swapnil,
I understand that you are trying to design a spur gear.
You can refer the following implementation shared on file exchange on MALTAB Central for the same. Please go through the GitHub repository mentioned on the following page for a better understating of how a spur gear can be implemented with MATLAB.
https://www.mathworks.com/matlabcentral/fileexchange/79721-spur-gear-designer
Hope this helps!

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