3D plot using time series
显示 更早的评论
I'm trying to create a 3D graph like the image below. I have attached a reduced data set of my results below. Does anyone know how this would work? 

I've currently tried surf and waterfall but I can't seem to get it working. It a mess but this is kind of what I've been working with
results.
In effect I want each day of the results to be shown on a different "slice"
%Sets Date time format for when table is read
opts = detectImportOptions("results.xlsx","Sheet","Sheet1");
opts = setvartype(opts,"Date","datetime");
opts = setvaropts(opts,"Date",'InputFormat','dd.MM. HH:mm');
results = readtable("results.xlsx",opts);
x = results.Efficiency;
y = results.Power;
% z = results.Date; % HOW DO YOU INCLUDE THIS?
[X,Y] = meshgrid(x,y);
Z = peaks(X,Y);
waterfall(X,Y,Z)
采纳的回答
results = readtable('https://www.mathworks.com/matlabcentral/answers/uploaded_files/980365/results.xlsx', 'VariableNamingRule','preserve');
results.Date = datetime(results.Date, 'InputFormat','MM.dd. HH:mm', 'Format','MM.dd. HH:mm')
results = 30×15 table
Date AmbientTemp SkyTemp GlassTemp PVTemp AbsorberTemp Irradiance WindSpeed Power WaterTemp WaterTemp2 Efficiency Hwind Kair Pb
____________ ___________ _______ _________ ______ ____________ __________ _________ ______ _________ __________ __________ ______ _____ _______
01.01. 00:00 300.3 287.26 287.26 286.89 286.5 0 3.7 0 0 289.95 0.19869 19.952 300.3 -1200
01.01. 01:00 299.5 286.11 286.11 285.77 285.41 0 3.2 0 0 289.43 0.19878 18.022 299.5 -1200
01.01. 02:00 298.6 284.82 284.82 284.35 283.85 0 4.8 0 0 288.68 0.19889 24.198 298.6 -1200
01.01. 03:00 299.3 285.82 285.82 285.31 284.77 0 5.5 0 0 289.12 0.19881 26.9 299.3 -1200
01.01. 04:00 298.8 285.11 285.11 284.62 284.1 0 5.1 0 0 288.8 0.19887 25.356 298.8 -1200
01.01. 05:00 299.1 285.54 285.54 285.13 284.71 0 4 0 0 289.09 0.19883 21.11 299.1 -1200
01.01. 06:00 299.1 285.54 285.86 285.47 285.04 12.9 4 2.5645 0 289.25 0.1988 21.11 299.1 -1197.4
01.01. 07:00 300 286.83 293.07 292.88 292.43 259 4.2 51.337 0 292.78 0.19821 21.882 300 -1148.7
01.01. 08:00 300.9 288.12 299.65 299.66 299.18 498 4.2 98.443 0 296 0.19768 21.882 300.9 -1101.6
01.01. 09:00 301.6 289.13 303.02 303.13 302.63 614 4.2 121.2 0 297.65 0.1974 21.882 301.6 -1078.8
01.01. 10:00 302.5 290.42 311.37 311.75 311.19 972 4.4 191.21 0 301.74 0.19672 22.654 302.5 -1008.8
01.01. 11:00 302.8 290.85 306.95 307.17 306.67 732 4.8 144.26 0 299.58 0.19708 24.198 302.8 -1055.7
01.01. 12:00 303 291.14 308.95 309.22 308.71 819 4.6 161.28 0 300.55 0.19692 23.426 303 -1038.7
01.01. 13:00 303.1 291.28 306.04 306.2 305.72 669 4.8 131.9 0 299.12 0.19716 24.198 303.1 -1068.1
01.01. 14:00 303 291.14 304.11 304.2 303.73 582 4.6 114.84 0 298.18 0.19732 23.426 303 -1085.2
01.01. 15:00 302.4 290.28 296.13 295.9 295.41 251 5.9 49.691 0 294.2 0.19797 28.444 302.4 -1150.3
x = results.Efficiency;
y = results.Power;
z = results.AmbientTemp;
xv = linspace(min(x), max(x), numel(x)); % Create Vector For Interpolation
yv = linspace(min(y), max(y), numel(y)); % Create Vector For Interpolation
[X,Y] = ndgrid(xv,yv); % Create Matrices For Interpolation
Z = griddata(x, y, z, X, Y); % Interpolate Matrix
figure
stem3(x, y, z, 'p', 'filled')
grid on
title('Stem Plot')

figure
surfc(X, Y, Z)
grid on
xlabel('Efficiency')
ylabel('Power')
zlabel('Temperature [°C]')
title('Surface Plot')

Experiment with this approach with your actual data.
.
4 个评论
That looks great thank you! Is there anyway of having x be the hour of the day and z be the day number within in the year?
My pleasure!
To do something similar to the original plot in the question, this works —
results = readtable('https://www.mathworks.com/matlabcentral/answers/uploaded_files/980365/results.xlsx', 'VariableNamingRule','preserve');
results.Date = datetime(results.Date, 'InputFormat','MM.dd. HH:mm', 'Format','MM.dd. HH:mm')
results = 30×15 table
Date AmbientTemp SkyTemp GlassTemp PVTemp AbsorberTemp Irradiance WindSpeed Power WaterTemp WaterTemp2 Efficiency Hwind Kair Pb
____________ ___________ _______ _________ ______ ____________ __________ _________ ______ _________ __________ __________ ______ _____ _______
01.01. 00:00 300.3 287.26 287.26 286.89 286.5 0 3.7 0 0 289.95 0.19869 19.952 300.3 -1200
01.01. 01:00 299.5 286.11 286.11 285.77 285.41 0 3.2 0 0 289.43 0.19878 18.022 299.5 -1200
01.01. 02:00 298.6 284.82 284.82 284.35 283.85 0 4.8 0 0 288.68 0.19889 24.198 298.6 -1200
01.01. 03:00 299.3 285.82 285.82 285.31 284.77 0 5.5 0 0 289.12 0.19881 26.9 299.3 -1200
01.01. 04:00 298.8 285.11 285.11 284.62 284.1 0 5.1 0 0 288.8 0.19887 25.356 298.8 -1200
01.01. 05:00 299.1 285.54 285.54 285.13 284.71 0 4 0 0 289.09 0.19883 21.11 299.1 -1200
01.01. 06:00 299.1 285.54 285.86 285.47 285.04 12.9 4 2.5645 0 289.25 0.1988 21.11 299.1 -1197.4
01.01. 07:00 300 286.83 293.07 292.88 292.43 259 4.2 51.337 0 292.78 0.19821 21.882 300 -1148.7
01.01. 08:00 300.9 288.12 299.65 299.66 299.18 498 4.2 98.443 0 296 0.19768 21.882 300.9 -1101.6
01.01. 09:00 301.6 289.13 303.02 303.13 302.63 614 4.2 121.2 0 297.65 0.1974 21.882 301.6 -1078.8
01.01. 10:00 302.5 290.42 311.37 311.75 311.19 972 4.4 191.21 0 301.74 0.19672 22.654 302.5 -1008.8
01.01. 11:00 302.8 290.85 306.95 307.17 306.67 732 4.8 144.26 0 299.58 0.19708 24.198 302.8 -1055.7
01.01. 12:00 303 291.14 308.95 309.22 308.71 819 4.6 161.28 0 300.55 0.19692 23.426 303 -1038.7
01.01. 13:00 303.1 291.28 306.04 306.2 305.72 669 4.8 131.9 0 299.12 0.19716 24.198 303.1 -1068.1
01.01. 14:00 303 291.14 304.11 304.2 303.73 582 4.6 114.84 0 298.18 0.19732 23.426 303 -1085.2
01.01. 15:00 302.4 290.28 296.13 295.9 295.41 251 5.9 49.691 0 294.2 0.19797 28.444 302.4 -1150.3
x = hour(results.Date);
y = day(results.Date, 'dayofyear');
z = results.AmbientTemp;
xv = linspace(min(x), max(x), numel(x)); % Create Vector For Interpolation
yv = linspace(min(y), max(y), numel(y)); % Create Vector For Interpolation
[X,Y] = ndgrid(xv,yv); % Create Matrices For Interpolation
Z = griddata(x, y, z, X, Y); % Interpolate Matrix
figure
stem3(x, y, z, 'p', 'filled')
grid on
xlabel('Hour')
ylabel('Day of Year')
zlabel('Temperature [°C]')
title('Stem Plot')

figure
surfc(X, Y, Z)
grid on
xlabel('Hour')
ylabel('Day of Year')
zlabel('Temperature [°C]')
title('Surface Plot')

That should also work with the larger data file.
The original plot has hours on the x-axis, days on the y-axis and temperature on the z-axis, so that is what I am doing here. If you want day on the z-axis, reverse the order of the arguments to the surf function —
figure
surfc(X, Z, Y)
grid on
xlabel('Hour')
zlabel('Day of Year')
ylabel('Temperature [°C]')
title('Surface Plot')

That looks a bit strange to me, however ‘mine is not to reason why ...’
.
Thank you Star Strider that's amazing!
As always, my pleasure!
To create different surface plots, change the ‘x’ and ‘y’ variables in my code to be the independent variables for the plot, and then use the appropriate ‘z’ vector in the griddata call. The code should be relatively robust to those changes.
更多回答(0 个)
类别
在 帮助中心 和 File Exchange 中查找有关 Surface and Mesh Plots 的更多信息
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!选择网站
选择网站以获取翻译的可用内容,以及查看当地活动和优惠。根据您的位置,我们建议您选择:。
您也可以从以下列表中选择网站:
如何获得最佳网站性能
选择中国网站(中文或英文)以获得最佳网站性能。其他 MathWorks 国家/地区网站并未针对您所在位置的访问进行优化。
美洲
- América Latina (Español)
- Canada (English)
- United States (English)
欧洲
- Belgium (English)
- Denmark (English)
- Deutschland (Deutsch)
- España (Español)
- Finland (English)
- France (Français)
- Ireland (English)
- Italia (Italiano)
- Luxembourg (English)
- Netherlands (English)
- Norway (English)
- Österreich (Deutsch)
- Portugal (English)
- Sweden (English)
- Switzerland
- United Kingdom (English)
