Eigenvalue vibrational response Two DOF spring- mass system
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A 2 degree of freedom (2 DOF) system with 3 springs only is given. I am little bit confused to write the codes. I would be glad for some help.
[ 1 0 𝒙̈(𝑡) + [ 12 −2 x(𝑡) = 0 and 𝒙̇(0) = 0 , 𝒙(0) = [1 1]^𝑇
0 4] 2 12]
So here, m1=1 and m2=4 while k1=k3=10 and k2=2. But I do not know why my code is wrong.
K1=10 ; K2=2 ; K3=10 ;
M1=1 ; M2=4 ;
M= [ M1 0 ;
0 M2] ;
K=[K1+K2 -K2;
-K2 K2+K3] ;
[modeShape fr]=eig (K,M); %estimation of natural frequenciesand mode shapes
A00=zeros(2); A11=eye(2);
CC=[A00 A11;-inv(M)*K A00];
global CC
max_freq=max(sqrt(diag(fr))/(2*pi)); %highest frequency in Hz
dt=1/(max_freq*20);
time=0:dt:200*dt;
y0=[1 1 0 0]; %[displ1 disp2 vel1 vel2] initial condition
plot(time,ysol(:,1:2),'linewidth',2)
xlabel ('Time')
ylabel('displacement')
ylim([-.02 .02])
grid on
2 个评论
Ali
2022-4-29
How did you know your code is wrong? Are you getting an error message or is the plot different than what you expect?
回答(1 个)
Gyan Vaibhav
2023-12-29
编辑:Gyan Vaibhav
2023-12-29
Hi Joni,
I understand that you are trying to solve a spring mass system with two degrees of freedom with 3 springs and 2 masses.
The code seems to have a good start on setting up the system for simulation, but there are a few issues and missing steps in the code that need to be addressed.
Here are a few points to be rectified:
- To find solutions with the conditions, a solver needs to be used. “ode45” can be used for this purpose.
- The outputs need to be stored and then the correct variable needs to be plotted. In the above code, “ysol” has been used to plot; however it was never defined, resulting in an error.
Here is the code with some corrections and improvements, to give the desired output, and better readability:
% Define system parameters
K1 = 10; K2 = 2; K3 = 10;
M1 = 1; M2 = 4;
% Mass matrix
M = [M1 0; 0 M2];
% Stiffness matrix
K = [K1+K2 -K2; -K2 K2+K3];
% Calculate eigenvalues and eigenvectors (mode shapes)
[modeShape, fr] = eig(K, M);
% Calculate natural frequencies in Hz
nat_freqs = sqrt(diag(fr)) / (2 * pi);
% Highest frequency in Hz
max_freq = max(nat_freqs);
dt = 1 / (max_freq * 20);
% Simulation time span
time_span = 0:dt:200*dt;
% Initial conditions [x1(0) x2(0) x1_dot(0) x2_dot(0)]
y0 = [1 1 0 0];
% State-space representation
A = [zeros(2), eye(2); -M\K, zeros(2)];
% ODE function
ode_func = @(t, y) A * y;
% Solve ODE
[time, ysol] = ode45(ode_func, time_span, y0);
% Plot the results
plot(time, ysol(:, 1:2), 'linewidth', 2);
xlabel('Time (s)');
ylabel('Displacement (m)');
ylim([-1.2 1.2]); % Adjust the y-axis limits if needed
grid on;
title('Displacement vs. Time for a 2 DOF System');
legend('Mass 1 Displacement', 'Mass 2 Displacement');
Please note the following corrections and additions:
- The ODE function “ode_func” is defined as a function handle.
- The ode45 solver is used to simulate the system response over the required time span.
- The plot function is corrected to plot the displacements.
Refer to the following documentation to learn more about “ode45” solver.
Hope this helps.
Thanks
Gyan
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