How to interpolate the given plot?
显示 更早的评论
I plot speed vs. width (the first three columns are the velocity components and the last the width, please see first file here https://drive.google.com/drive/folders/1CgeDuCahVZvLXXkNkGWlPg8lSGyurmI3) using the following code
clc
close all
clear all
warning('OFF', 'MATLAB:table:ModifiedAndSavedVarnames')
%step 0
Qi = readmatrix("004timestepN2Void30mm.csv");
[v,w] = size(Qi);
%step 1
fCom_004 = Qi(:,1);
sCom_004 = Qi(:,2);
tCom_004 = Qi(:,3);
width_004 = [0;Qi(:,w)+0.0075];
U_004 = sqrt(fCom_004.^2 + sCom_004.^2 + tCom_004.^2);
refined_U_004 = [0;U_004];
%step 3
figure
plot(width_004,refined_U_004)
legend('0.004 timestep','Location','bestoutside')
xlabel('width [m] | 30mm profile')
ylabel('U magnitude [m/s]')
axis square;
grid on;
You'll see that the peak is far from being smooth. To fix the issue I am trying to use interpolation. To do so I modified step 3
newX = linspace (0, 0.015,3e3);
newY = interp1(width_0002,refined_U_0002,newX);
figure
plot(newX,newY)
legend('0.004 timestep','Location','bestoutside')
xlabel('width [m] | 30mm profile')
ylabel('U magnitude [m/s]')
axis square;
grid on;
But the following error pops up "Sample points must be unique."
I think I know why this is happening.
By default, Matlab seems to only read the first four decimals of a given number. Notice that in the last column many numbers only differ from the fifth number; that's why Matlab sees them as equal.
Assuming that I am right, how to make Matlab read the full given numbers of a file?
Thanks in advance! :)
采纳的回答
MATLAB reads what it is given.
%step 0
Qi = readmatrix("JD_PM sampleData30mm.csv");
[v,w] = size(Qi);
%step 1
fCom_004 = Qi(:,1);
sCom_004 = Qi(:,2);
tCom_004 = Qi(:,3);
width_004 = [0;Qi(:,w)+0.0075];
U_004 = sqrt(fCom_004.^2 + sCom_004.^2 + tCom_004.^2);
refined_U_004 = [0;U_004];
%step 3
figure
plot(width_004,refined_U_004)
legend('0.004 timestep','Location','bestoutside')
xlabel('width [m] | 30mm profile')
ylabel('U magnitude [m/s]')
axis square;
grid on;
% % You'll see that the peak is far from being smooth. To fix the issue I am trying to use interpolation. To do so I modified step 3
newX = linspace (0, 0.015,3e3);
[width_004,idx] = unique(width_004, 'stable'); % Eliminate Duplicates
newY = interp1(width_004,refined_U_004(idx),newX);
figure
plot(newX,newY)
legend('0.004 timestep','Location','bestoutside')
xlabel('width [m] | 30mm profile')
ylabel('U magnitude [m/s]')
axis square;
grid on;
I tried different interpolation methods ('pchip', 'spline') and do not see a difference.
.
2 个评论
JD_PM
2022-4-28
My pleasure!
One option is to develop a nonlinear model for that and fit the data to it.
%step 0
Qi = readmatrix('https://www.mathworks.com/matlabcentral/answers/uploaded_files/982200/JD_PM%20sampleData30mm.csv');
[v,w] = size(Qi);
%step 1
fCom_004 = Qi(:,1);
sCom_004 = Qi(:,2);
tCom_004 = Qi(:,3);
width_004 = [0;Qi(:,w)+0.0075];
U_004 = sqrt(fCom_004.^2 + sCom_004.^2 + tCom_004.^2);
refined_U_004 = [0;U_004];
%step 3
figure
plot(width_004,refined_U_004)
legend('0.004 timestep','Location','bestoutside')
xlabel('width [m] | 30mm profile')
ylabel('U magnitude [m/s]')
axis square;
grid on;
% % You'll see that the peak is far from being smooth. To fix the issue I am trying to use interpolation. To do so I modified step 3
newX = linspace (0, 0.015,3e3);
[width_004,idx] = unique(width_004, 'stable'); % Eliminate Duplicates
newY = sgolayfilt(refined_U_004(idx), 3, 81); % Use 'sgolayfilt'
figure
plot(width_004,newY)
legend('0.004 timestep','Location','bestoutside')
xlabel('width [m] | 30mm profile')
ylabel('U magnitude [m/s]')
axis square;
grid on;
Change the ‘framelen’ value to get the desired result.
The smoothdata function has an ‘sgolay’ option, however I do not know if that requires the Signal Processing Toolbox as well.
.
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Graphics Object Properties 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
