A = [0 1 0 0 1 0 0
1 0 0 0 0 1 0
1 0 0 1 0 1 1
1 1 0 0 1 1 0
1 1 1 0 1 1 0
1 1 0 0 1 1 0 ];
1)
This is a 6x7 matrix. I wanted to check each row to see if it finds [0 0 0 0] and then if it finds it, then store it into a vector.
Can this be done with a nested for loop?
The way I wanted it to check for [0 0 0 0] for each row is as follows:
Row 1: A(1, 1:4), A(1,2:5), A(1,3:6), A(1,4:7)
Row 2: A(2, 1:4), A(2,2:5), A(2,3:6), A(2,4:7)
Row 3: A(3, 1:4), A(3,2:5), A(3,3:6), A(3,4:7)
etc...up until row 6.
2)
Also can this done for each column using for loops also? Check if it finds [1 1 1 1]' in each column?
Column 1: A(1:4, 1), A(2:5,1), A(3:6,1)
Column 2: A(1:4, 2), A(2:5,2), A(3:6,2)
etc...up until column 7
OR
Is there any easier method not using any fancy built in functions and just using for loops and if/else conditionals?
