Hi Jacob,
I understand that you want to detect the decimal points when reading a line with numbers and decimals, while avoiding detecting any dot as decimal.
You can follow below steps:
- Segment the digits in the line. Segmenting the individual digits in the line will help you do contextual analysis.
- Identify the position of digits and their relationship to the nearby dots. For instance, if a dot is located between two digits, it is more likely to represent a decimal point.
- Find patterns that suggest the presence of a decimal number. For instance, search for digit sequences that are followed by a dot and then additional digits, as this is a typical way to identify a decimal number.
Refer the following pseudo code for better understanding:
% Assuming you have already segmented the input line into individual characters. Refer the documentation below for exploring various segmentation process in the image.
inputLine = 'Your input line containing numbers and decimals';
characters = convertInputLineToCharacters(inputLine); % Convert the input line to individual characters, using the function you have written for your use case (I have provided a pseudo function name, replace it with your function).
for i = 1:length(characters)
currentChar = characters{i};
% Perform contextual analysis to distinguish decimal points from regular dots
if istrcmp(previousChar, '.') % Check if the current character is a dot
% Check the neighbouring characters to determine if the current dot is a decimal point
if i > 2 && i < length(characters)-1
previousChar = characters{i-1};
nextChar = characters{i+1};
if isdigit(previousChar) && isdigit(nextChar)
% The dot is likely a decimal point
% Perform appropriate processing for decimal numbers
end
end
else
% Perform processing for non-digit characters
end
end
For more information on various segmentation techniques for images and “OCR” function refer the links below:
- Segmentation Techniques: https://www.mathworks.com/help/images/image-segmentation.html
- “OCR” function: https://www.mathworks.com/help/vision/ref/ocr.html
Regards,
Ayush
