Index in Positon 1 is invalid

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Jan Faber
Jan Faber 2022-4-29
回答： Jan Faber 2022-4-29
Hello everyone, sadly I have an error that I personally don't really understand, maybe one of you will able to help me, so thanks a lot in advance for that.
So for a task for the university I'm trying to shorten the script a lot by creating a vector through a loop, but I constantly get the error that my Index is invalid.
My aim is to get a 0:14 long vector that contains the following equation for each row depending on n, but sadly it isn't working as planed, i would be really grateful if someone could help me to find my problem here.
for n=0:14
x1=5*sin(2*pi*F1*(kT-n*T));
x2=0.3*cos(2*pi*F2*(kT-n*T));
x=x1+x2;
xv(n,:)=x
end
Error: Index in position 1 is invalid. Array indices must be positive integers or logical values.
Sincerely Jan C. Faber

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采纳的回答

Voss
Voss 2022-4-29
Indexing in MATLAB starts at 1, so when n == 0, referring to xv(n,:) gives you that error.
One way to fix it is to add 1 to n when you use it as an index, so that n = 0 through n = 14 correspond to rows 1 through 15 of xv:
for n=0:14
x1=5*sin(2*pi*F1*(kT-n*T));
x2=0.3*cos(2*pi*F2*(kT-n*T));
x=x1+x2;
% xv(n,:)=x
xv(n+1,:)=x
end

更多回答（2 个）

Steven Lord
Steven Lord 2022-4-29
MATLAB indexing is 1-based not 0-based.
The first element / row / column / etc. of an array in MATLAB is element / row / column / etc. 1 not 0.
Jan Faber
Jan Faber 2022-4-29
If I could, then I would love to accept both answers, thanks a lot both of you.

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