getting an error in this code
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clc
clear
%shipcostpmf.m
sx = (1:8);
px = [0.15*ones(4,1), 0.1*ones(4,1)];
gx = (sx<=5).*(105*sx-5*(sx.^2)) + ((sx>5).*500);
sy = unique(gx);
fprintf('sy =\n');
disp(sy);
py = finitepmf(gx,px,sy);
not sure why my py is getting an error because it says Unrecognized function or variable 'finitepmf'. but finitepmf should be a command?
采纳的回答
Mahmoud Ashraf
2022-4-29
you should define funstion of finitrepmf
as shown in this code
clc
clear
%shipcostpmf.m
sx = (1:8);
px = [0.15*ones(4,1), 0.1*ones(4,1)];
gx = (sx<=5).*(105*sx-5*(sx.^2)) + ((sx>5).*500);
sy = unique(gx);
fprintf('sy =\n');
disp(sy);
py = finitepmf(gx,px,sy);
function pmf=finitepmf(sx,px,x)
% finite random variable X:
% vector sx of sample space
% elements {sx(1),sx(2), ...}
% vector px of probabilities
% px(i)=P[X=sx(i)]
% Output is the vector
% pmf: pmf(i)=P[X=x(i)]
pmf=zeros(size(x(:)));
for i=1:length(x)
pmf(i)= sum(px(find(sx==x(i))));
end
end
更多回答（2 个）
Voss
2022-4-29
Maybe finitepmf should be defined as follows:
function pmf=finitepmf(sx,px,x)
% finite random variable X:
% vector sx of sample space
% elements {sx(1),sx(2), ...}
% vector px of probabilities
% px(i)=P[X=sx(i)]
% Output is the vector
% pmf: pmf(i)=P[X=x(i)]
pmf=zeros(size(x(:)));
for i=1:length(x)
pmf(i)= sum(px(find(sx==x(i))));
end
end
which was found here:
If that seems right and you haven't done so already, put that code into an m-file called finitepmf.m. If you have done that already, then make sure that finitepmf.m is on your MATLAB search path.
Mathieu NOE
2022-4-29
hi
here you are
sx = (1:8);
px = [0.15*ones(4,1), 0.1*ones(4,1)];
gx = (sx<=5).*(105*sx-5*(sx.^2)) + ((sx>5).*500);
sy = unique(gx);
fprintf('sy =\n');
disp(sy);
py = finitepmf(gx,px,sy)
function pmf=finitepmf(sx,px,x)
% finite random variable X:
% vector sx of sample space
% elements {sx(1),sx(2), ...}
% vector px of probabilities
% px(i)=P[X=sx(i)]
% Output is the vector
% pmf: pmf(i)=P[X=x(i)]
pmf=zeros(size(x(:)));
for i=1:length(x)
pmf(i)= sum(px(sx==x(i)));
end
end
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