Using break/continue in a for loop

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Sherwin 2022-4-30

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1708580-using-break-continue-in-a-for-loop

评论： Image Analyst 2022-4-30

I have this loop and I want the second loop to have steps with different sizes and I need the inner loop to end after each iteration and go to the next e:

N = 4;
ODN = [ 4 5 4 4];
NP = 17;
ODD = [10000 10000, 5000 5000];
for e = 1:N
            for f = 1:ODN(e,1):NP
                L = tp(f:ODN(e,1),1);
                [X,Y] = min(L,[],1);
                xpC(Y,1) = ODD(f,1);
                continue
            end
end

if I use continue it will continue the inner loop ( which I don't want and if I use break instead, it will reset f to 1. What can I do to get what I want?

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采纳的回答

Image Analyst 2022-4-30

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1708580-using-break-continue-in-a-for-loop#answer_954235

在 MATLAB Online 中打开

Reverse the order of the e anf f loops:

N = 4;
ODN = [ 4 5 4 4];
NP = 17;
ODD = [10000 10000, 5000 5000];
for f = 1:ODN(e,1):NP
    for e = 1:N
        L = tp(f:ODN(e,1),1);
        [X,Y] = min(L,[],1);
        xpC(Y,1) = ODD(f,1);
    end
end

Now after it does this

L = tp(f:ODN(e,1),1);
[X,Y] = min(L,[],1);
xpC(Y,1) = ODD(f,1);

once, it will move to the next e in the list.

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Sherwin 2022-4-30

sorry I didn't understand the question before. Yes the second one is what I want:

e=1, f=1

e=2, f=5

e=3, f=10

e=4, f=14

Image Analyst 2022-4-30

在 MATLAB Online 中打开

You just need one loop to have them both increment in synchrony:

N = 4;
ODN = [ 4 5 4 4];
NP = 17;
ODD = [10000 10000; 5000 5000];
e = [1 2 3 4]
f = [1 5 10 14]
for k = 1 : length(f)
    thisf = f(k);
    thise = e(k);
    L = tp(thisf:ODN(thise,1),1);
    [X,Y] = min(L,[],1);
    xpC(Y,1) = ODD(thisf,1);
end