Problem with ploting exp function
显示 更早的评论
I try to plot t(x,y) = (x^2 - 2y^2)*e^(x-y) in Matlab and i use the following code
t=@(x,y)((x.^2-2*y.^2).*exp(x-y));
x = -1:2/50:1;
y = -2:4/50:2;
[X, Y] = meshgrid(x, y);
surf(X, Y, t(X,Y));
rotate3d on;
I got the result but it is not the same as i drawn in Geogebra
I think there is a problem with .*exp(x-y)
4 个评论
Alberto Cuadra Lara
2022-5-2
Hello Dinh,
The function looks good. Are you using the same limits in Geogebra?
Dinh Le Dung
2022-5-3
This is what Matlab gives
This is what Geogebra gives.
They look pretty much not the same :((
Walter Roberson
2022-5-3
Very different plotting ranges.
Dinh Le Dung
2022-5-3
采纳的回答
"I think there is a problem with .*exp(x-y)"
I doubt that. Did you look at the domains and ranges that you are plotting?
Your Geogebra example shows that you plotted over x = -8..+8 and y = -8..+8. Then in MATLAB you plotted over x = -1..1 and y = -2..2. And then you did not limit the Z axes to the same range as your example plot. Lets try that now:
x = -8:0.5:8;
y = -8:0.5:8;
[X,Y] = meshgrid(x,y);
T = (X.^2-2*Y.^2).*exp(X-Y);
surf(X,Y,T);
zlim([-3,6])
更多回答（1 个）
Catalytic
2022-5-2
If I had to guess, you have x and y reversed.
[X, Y] = ndgrid(x, y);
surf(X, Y, t(X,Y));
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