Trigonometric equation solving matlab
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syms a1 a2 theta1 theta2
alpha1=-(pi/2);
alpha2=0;
When i am solving the following equation in command prompt. sin(theta1)*cos(alpha1)
ans =
-(4035888341267763*sin(theta1))/9007199254740992
Now i need the output as -sin(theta1) because cos(-90) is -1. I need to round of the decimal value.
采纳的回答
John D'Errico
2015-1-22
编辑：John D'Errico
2015-1-22
0 个投票
HUH? The solution you show in ans does not follow from what you have written above that. So it is literally impossible to know what you are doing since you have not provided useful information for us to answer.
Anyway, you need to learn to use vpa. This will resolve those long integers that the symbolic TB tends to generate.
3 个评论
Ajay
2015-1-22
John D'Errico
2015-1-22
编辑：John D'Errico
2015-1-22
You are not listening to what I said. If alpha1 is -pi/2, then the result you show does not match reality, in ANY way, shape or form.
syms theta1
alpha1 = sym(-pi/2);
sin(theta1)*cos(alpha1)
ans =
0
This happens because the toolbox knows that cos(-pi/2) is zero, not even -1 as you claim.
cos(alpha1)
ans =
0
I think your problem is you have posted a question that does not represent what you actually did. In fact, I CAN reproduce your error, if I do something completely different.
vpa(cos(sym(90)))
ans =
-0.44807361612917015236547731439964
vpa('-(4035888341267763*sin(theta1))/9007199254740992')
ans =
-0.44807361612917018245383360408596*sin(theta1)
Do you notice the similarity between those numbers? Look carefully. Now, read the help for cos. MATLAB assumes the input to the cos function is in radians. How is it to know that when you type cos(-90), that you actually WANTED it to compute the cosine of the angle -90 DEGREES? It computes the cos of -90 RADIANS, as it must. MATLAB cannot read your mind.
When you see something strange, THINK about what you are doing. And when you post a question, post what you actually did, not something completely different.
Ajay
2015-1-26
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