Replacing non-alphabetic characters with numbers?

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Andrew
Andrew 2015-1-22
回答： Matz Johansson Bergström 2015-1-22
Hello everyone,
I'm trying to solve a question and it's asking me to take the variable:
TS1='%@3Gb6'
and convert the non-alphabetic characters to zeros and the alphabetic characters with ones, saving the result as a new variable. Ideally I'm trying to get a new variable to saves as:
result=[0 0 0 1 1 0]
I would greatly appreciate the help on this issue.

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2015-1-22
编辑：Azzi Abdelmalek 2015-1-22
out=zeros(size(TS1));
out(regexpi(TS1,'[A-Z]','start'))=1
%OR
str=['A':'Z' 'a':'z'];
out=ismember(TS1,str)

更多回答（1 个）

Matz Johansson Bergström
Yet another answer, just for the "cellfun" of it ;-)
tmp = cellfun(@(x) isstrprop(x, 'alpha'), {TS1}, 'UniformOutput', false);
out = cell2mat(tmp)
First, check the property of each element (cellfun does this) of the cell array {TS1}, if 'alpha' then 1 otherwise 0. Then we need to convert to a matrix, which is a vector in this case. If you wish to sum the ones in the vector you might want to convert it to "double", it is logical now.

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