Error: Function definitions are not permitted in this context.

Question

Nabin SUNAM 2015-1-22

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https://ww2.mathworks.cn/matlabcentral/answers/171230-error-function-definitions-are-not-permitted-in-this-context

编辑： Walter Roberson 2021-5-17

采纳的回答： Image Analyst

This is my function

function [ area ] = calcarea(rad )

area = pi*rad.^2

end

When I try to run it, following message shows up, "The selected section cannot be evaluated because it contains an invalid statement

Also, the command window says "Error: Function definitions are not permitted in this context"

What am I doing wrong???

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Nabin SUNAM 2015-1-23

It worked after I saved the file with the same filename as my function, i.e my filename was not calcarea.m before, once I renamed the filename as calcarea.m, it started functioning. I had to call the function in the command window though.

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Answer 1

Image Analyst 2015-1-23

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在 MATLAB Online 中打开

You probably have that function below a script in your m-file. You can't mix a script and a function in the same file. You can have two functions though. So if your file is called test.m, you could have all this in the single file:

function test()
    area = calcarea(10)
end
function area = calcarea(rad)
    area = pi*rad.^2;
end

Or you could have them in two separate files:

A script in test.m:

area = calcarea(10)

A function in calcarea.m:

function area = calcarea(rad)
    area = pi*rad.^2;
end

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Image Analyst 2018-3-6

Attach your m-file(s) in a new question (not here in Nabin's question).

Walter Roberson 2018-3-6

Sanjiv Kumar what happened when you followed the instructions I gave in your Question to install the contents of the .zip I provided for you?

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Answer 2

Star Strider 2015-1-22

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在 MATLAB Online 中打开

You have to put functions such as yours in their own separate .m-files. In your situation, you would save it as: calcarea.m, and to run it from your main script, you would call it as:

area = calcarea(rad)

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Nabin SUNAM 2015-1-23

Yes, my problem was I saved the file with different filename. It started working when I renamed the file. Thanks for the quick reply.

Star Strider 2015-1-23

My pleasure!

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Answer 3

bahadir safak 2016-12-17

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编辑：Walter Roberson 2018-3-6

在 MATLAB Online 中打开

sigma=1;
thresh=1000;
disp=1;
radius=1
im=imread('11.jpg');
function [cim, r, c] = harris(im, sigma, thresh, radius, disp)
      error(nargchk(2,5,nargin));
      dx = [-1 0 1; -1 0 1; -1 0 1]; % Derivative masks
      dy = dx';
      Ix = conv2(im, dx, 'same');    % Image derivatives
      Iy = conv2(im, dy, 'same'); 
??? Error: File: harris1.m Line: 45 Column: 1
Function definitions are not permitted in this context.
>>

???

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Mohammedashraf Shaikh 2017-5-4

编辑：Walter Roberson 2018-3-6

在 MATLAB Online 中打开

function[d] = hcompare_EMD(h1,h2)
d = sum(abs(cumsum(h1) - cumsum(h2)));
end
img = imread('C:\Users\Hp\Desktop\col\001.jpg');
function[h] = histImage(img)
% This function calculates normalized histogram of image.
% Normalized histogram is histogram h, that has at
% each i place in it, value:
% (number of picture pixels with gray level i-1) / 
% (total num of pixels in picture).
sum = 0;
[y,x] = size(img); % getting sizes of image 
h = zeros(1,256);    % creating output histogram array
for i = 1:1: y     % runing on rows
      for j = 1:1: x % running on colomns
          % gray level is addtess to cell in output histogram array
     % we add there 1 (bacause of current pixel (y,x) has this gray level
h(img(i,j)) = h(img(i,j)) + 1;
          % pay attention to fact, that we use here pixel value as index!
      end
  end
h = h./(y*x);
end
% to calculate the distance between the histograms of the two images %%
 %(histArray, histPattern):
function[dmap] = patDistMAp(histArray, histPattern)
[y,x,z] = size(histArray);
dmap = zeros(y,x);                  % output array
for i = 1:1: y       % runing on rows
      for j = 1:1: x   % running on colomns
          hist = histArray(i,j,:);
%         for k = 1:1:256             % making array 1x256 from 1x1x256
%             h1(k) = hist(1,1,k);    % there is a permute function,
%         end                         % but we will use it next time)
          h1 = permute(squeeze(hist),[2,1]);
          % Using temp variable, as MATLAB7 wants it:
          temp = hcompare_EMD(histPattern,h1);
          dmap(i,j) = temp;
      end
end
end

Stephen23 2017-5-4

编辑：Stephen23 2017-5-4

在 MATLAB Online 中打开

@Mohammedashraf Shaikh: your code is badly aligned, and this makes hiding the errors easy. Once I correctly aligned your code and put each operation on its own line, then the (first) mistake is obvious, and occurs in the first five lines of code:

function[d] = hcompare_EMD(h1,h2)
d = sum(abs(cumsum(h1) - cumsum(h2)));
end
img = imread('C:\Users\Hp\Desktop\col\001.jpg');
function[h] = histImage(img)
...

You call img = ... outside of any function.

It is also possible that your first function definition occurs after some lines of code in a script. Depending on MATLAB version, this will also cause an error. See the other answers for more info on this.

Summary: Learn to align your code consistently (use the MATLAB defaults), and do not put multiple operators onto one line (especially the end for functions!). You can automatically align the code in the MATLAB Editor: select all code, then press ctrl+i.

Image Analyst 2017-5-4

And learn to format your posts by watching this tutorial Click here

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Answer 4

Rwigema james 2017-7-7

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编辑：Image Analyst 2017-7-7

在 MATLAB Online 中打开

function Iout = readAndPreprocessImage(filename)
        I=imread(filename);
        if ismatrix(I)
            I = cat(3,I,I,I);
       end
       Iout = imresize(I,[227 227]);
end

Why am I getting this error?????

Function definitions are not permitted in this context.

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Image Analyst 2017-7-7

You're putting the function definition in a place where it does not belong, such as below a script in release R2016a and earlier, or elsewhere.

Abbas Khreis 2021-5-16

i have 2016a version and the error Function definitions are not permitted in this con

plz help me

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Answer 5

Elena MEZZAPESA 2017-11-16

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Hello, Did you solve the issues to this problem in the end? As of 2017 I still get this error ?! I am trying to understand if it is because I am using a trial version of the software. Best regards,

Elena

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Image Analyst 2017-11-16

It was masked as being solved. The trial version is no different than a full version other than being time-limited to 30 days. We'd have to see your code to figure out what's going wrong with your program.

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Answer 6

Frieder Wittmann 2018-5-27

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This is one of the main disadvantages of MATLAB notebooks over Jupyter (python) notebooks. If I can't define functions in the middle of a script, the notebook becomes hard to read.

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Walter Roberson 2021-5-17

MATLAB is not Jupityr.

Frieder Wittmann 2021-5-17

编辑：Frieder Wittmann 2021-5-17

It isn't, it's one of the most common competitors.

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Error: Function definitions are not permitted in this context.

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