Cut measured data, time series shifted
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Hello, attached I have some measured data. I want now cut the data until 0,6 seconds.
So I want that the plot is beginning at 0,6 with the time 0 seconds. How I can do that
M1 = readmatrix('1antastenz.dat'); %Anfahrtsbewegeung
M = [M1];
% plot force data
subplot(2,1,1)
plot(M(:,1)/1000,M(:,2))
hold on
plot(M(:,1)/1000,M(:,3))
hold on
plot(M(:,1)/1000,M(:,4))
hold on
legend('Fx','Fy','Fz')
grid on
h_xlabel = xlabel ({ '$t$\,/\,s'});
set(h_xlabel,'Interpreter','latex');
h_ylabel = ylabel ({'$F$\,/\,N'});
set(h_ylabel,'Interpreter',' latex');
% plot torque data
subplot(2,1,2)
plot(M(:,1)/1000,M(:,5))
hold on
plot(M(:,1)/1000,M(:,6))
plot(M(:,1)/1000,M(:,7))
legend('Mx','My','Mz')
grid on
h_xlabel = xlabel ({ '$t$\,/\,s'});
set(h_xlabel,'Interpreter','latex');
h_ylabel = ylabel ({'$M$\,/\,Nmm'});
set(h_ylabel,'Interpreter',' latex');
grid on
h_xlabel = xlabel ({ '$t$\,/\,s'});
set(h_xlabel,'Interpreter','latex');
h_ylabel = ylabel ({'$Weg$\,/\,mm'});
set(h_ylabel,'Interpreter',' latex');
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回答(1 个)
Geoff Hayes
2022-5-5
@Mark S - since the first column on M corresponds to time, and since you divide that column by 1000, you would want to find all or at least the first element of that column that is greater than or equal to 600 (as 600/1000 = 0.6). So you could do something like
firstIndexSatisfyingCondition = find(M(:,1) >= 600,1);
We need only consider the first index since we assume that the column values are in increasing order. Then you can do
% plot force data
subplot(2,1,1)
plot(M(firstIndexSatisfyingCondition:end,1)/1000,M(firstIndexSatisfyingCondition:end,2))
hold on
plot(M(firstIndexSatisfyingCondition:end,1)/1000,M(firstIndexSatisfyingCondition:end,3))
hold on
plot(M(firstIndexSatisfyingCondition:end,1)/1000,M(firstIndexSatisfyingCondition:end,4))
hold on
I haven't tried the above but I hope the idea is clear.
3 个评论
Geoff Hayes
2022-5-9
@Mark S - won't that be misleading if you change the time (shift) from 0.6 to 0.0 seconds?
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