creating a Dummy variable from a string vector

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Ruben Moreno
Ruben Moreno 2022-5-13
回答： Walter Roberson 2022-5-13
Hi, i want to create a dummy variable of a string columnn cointaining information over investors. I have identified the names of the investors that i demme to have experience and would like to create a dummy = 1 if the cell contain the name of said investor, and 0 if not. The dataset is quite large so cant do this manually, not really sure how to proceed.
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Walter Roberson
Walter Roberson 2022-5-13
When you say "contains" do you mean that you want to compare the entries for exact equality? Or should "sam" be considered to be contained in "assam" or "samuel"? Should the comparison be case sensitive? Should "Billie-Joe" be considered the same as "Billie Joe"?
Ruben Moreno
Ruben Moreno 2022-5-13
I think i solved the problem in excel, but basically vlookup one column (investor name) with another(experienced investor) assign value 1 / 0.
The format of the investor names are the same throughout the sample, so exact match.

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回答（2 个）

Steven Lord
Steven Lord 2022-5-13
Ran in:
Use the string manipulation and/or set membership functions. Let's start with a random set of names:
rng default
D = ["Doc"; "Grumpy"; "Happy"; "Sleepy"; "Bashful"; "Sneezy"; "Dopey"];
randomDwarfs = D(randi(numel(D), [20 1]))
randomDwarfs = 20×1 string array
"Sneezy" "Dopey" "Doc" "Dopey" "Bashful" "Doc" "Grumpy" "Sleepy" "Dopey" "Dopey" "Grumpy" "Dopey" "Dopey" "Sleepy" "Sneezy" "Doc" "Happy" "Dopey" "Sneezy" "Dopey"
We can use matches to look for an exact match; startsWith, endsWith, or contains to look for text inside a name; or ismember to ask for members of a group of names.
onlyGrumpy = matches(randomDwarfs, "Grumpy");
startsWithD = startsWith(randomDwarfs, "D"); % Doc, Dopey
bashfulOrSleepy = ismember(randomDwarfs, ["Bashful"; "Sleepy"]);
results = table(randomDwarfs, onlyGrumpy, startsWithD, bashfulOrSleepy)
results = 20×4 table
randomDwarfs onlyGrumpy startsWithD bashfulOrSleepy ____________ __________ ___________ _______________ "Sneezy" false false false "Dopey" false true false "Doc" false true false "Dopey" false true false "Bashful" false false true "Doc" false true false "Grumpy" true false false "Sleepy" false false true "Dopey" false true false "Dopey" false true false "Grumpy" true false false "Dopey" false true false "Dopey" false true false "Sleepy" false false true "Sneezy" false false false "Doc" false true false
I can extract the names from randomDwarfs using those logical vectors.
BorS = randomDwarfs(bashfulOrSleepy)
BorS = 3×1 string array
"Bashful" "Sleepy" "Sleepy"
Walter Roberson
Walter Roberson 2022-5-13
ismember(investors, experiencedinvestors)

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