replace matrix A with the values of another matrix B

2022 5 15
2 个回答
回答已采纳
更新时间：2022 5 15
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Having a matrix A as attached, how to replace all those 1 in A with the values in matrix B, so that i get a new matrix as newA
A(:,:,1) =
0 0 1
0 1 0
0 1 1
A(:,:,2) =
1 0 0
0 0 0
0 0 0
A(:,:,3) =
0 1 0
1 0 1
1 0 0
B = [6 1 5; 2 6 7; 4 6 9];
B =
6 1 5
2 6 7
4 6 9
newA(:,:,1) =
0 0 5
0 6 0
0 6 9
newA(:,:,2) =
6 0 0
0 0 0
0 0 0
newA(:,:,3) =
0 1 0
2 0 7
4 0 0

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 采纳的回答

Bruno Luong
Bruno Luong 2022-5-15
编辑：Bruno Luong 2022-5-15
Ran in:

1 个投票

Ran in:
A= cat(3, [ 0 0 1;
0 1 0;
0 1 1], ...
[1 0 0,
0 0 0;
0 0 0], ...
[0 1 0;
1 0 1;
1 0 0 ]);
B = [6 1 5; 2 6 7; 4 6 9];
A.*B
ans =
ans(:,:,1) = 0 0 5 0 6 0 0 6 9 ans(:,:,2) = 6 0 0 0 0 0 0 0 0 ans(:,:,3) = 0 1 0 2 0 7 4 0 0

更多回答（1 个）

Dyuman Joshi
Dyuman Joshi 2022-5-15
编辑：Dyuman Joshi 2022-5-15
Ran in:

2 个投票

Ran in:
A(:,:,1) = [0 0 1; 0 1 0; 0 1 1];
A(:,:,2) = [1 0 0; 0 0 0; 0 0 0];
A(:,:,3) = [0 1 0; 1 0 1; 1 0 0];
B = [6 1 5; 2 6 7; 4 6 9];
newA=A.*B
newA =
newA(:,:,1) = 0 0 5 0 6 0 0 6 9 newA(:,:,2) = 6 0 0 0 0 0 0 0 0 newA(:,:,3) = 0 1 0 2 0 7 4 0 0

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