Problems with declaring the variable right

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Jan Faber
Jan Faber 2022-5-15
评论： Voss 2022-5-15
Good day everyone, sadly I got the following problem with my current task that I don't know how to define the right variable for the current calculation:
for i= 0:14
xkt1(i+1)= xg*sin(2*pi*F1*(k1.*T-i*T));
end
with:
xg= 7*2*5*1*6*3;
xh= 3/10;
F1=3;
F2=100;
T= 1/500;
xkt1=zeros(0:14);
xkt2=zeros(0:14);
k1 is the variable and I tried syms, @(k1) and k1=[ ];, sadly nothing worked and either it had problems of converting it into double, or simply wasnt able to use it correctly, if someone with more knowledge about matlab could help me, I would be really grateful.
Sincerely
Jan C. Faber

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采纳的回答

Voss
Voss 2022-5-15
Ran in:
Using symbolic k1 and xkt1:
syms k1 xkt1
xg= 7*2*5*1*6*3;
xh= 3/10;
F1=3;
F2=100;
T= 1/500;
for i= 0:14
xkt1(i+1)= xg*sin(2*pi*F1*(k1.*T-i*T));
end
xkt1
xkt1 = 
% evaluate xkt1(1) at k1 = 0, get a symbolic expression:
subs(xkt1(1),k1,0)
ans = 
0
% evaluate xkt1(1) at k1 = 0, get a numeric value:
double(subs(xkt1(1),k1,0))
ans = 0
% evaluate xkt1(2) at k1 = 0, get a symbolic expression:
subs(xkt1(2),k1,0)
ans = 
% evaluate xkt1(2) at k1 = 0, get a numeric value:
double(subs(xkt1(2),k1,0))
ans = -47.4896
Alternatively, using a cell array of anonymous functions:
xg= 7*2*5*1*6*3;
xh= 3/10;
F1=3;
F2=100;
T= 1/500;
xkt1=cell(1,15);
for i= 0:14
xkt1{i+1}= @(k1)xg*sin(2*pi*F1*(k1.*T-i*T));
end
xkt1
xkt1 = 1×15 cell array
{@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))} {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))} {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))} {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))} {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))} {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))} {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))} {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))} {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))} {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))} {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))} {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))} {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))} {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))} {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}
% evaluate xkt1{1} at k1 = 0:
xkt1{1}(0)
ans = 0
% evaluate xkt1{2} at k1 = 0:
xkt1{2}(0)
ans = -47.4896
  2 个评论
Jan Faber
Jan Faber 2022-5-15
Thanks a lot, I'll definitely give those options a try, when it should've worked, then I'll mark the answer as accepted.
Sincerely
Jan C. Faber
Voss
Voss 2022-5-15
Sounds good. Let me know if you have any questions about it.
-_

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更多回答（1 个）

Torsten
Torsten 2022-5-15
编辑：Torsten 2022-5-15
xg= 7*2*5*1*6*3;
xh= 3/10;
F1=3;
F2=100;
T= 1/500;
fun = @(k1,i) xg*sin(2*pi*F1*(k1-i)*T);
fun(14,0:14)

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