Problems with declaring the variable right
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Good day everyone, sadly I got the following problem with my current task that I don't know how to define the right variable for the current calculation:
for i= 0:14
xkt1(i+1)= xg*sin(2*pi*F1*(k1.*T-i*T));
end
with:
xg= 7*2*5*1*6*3;
xh= 3/10;
F1=3;
F2=100;
T= 1/500;
xkt1=zeros(0:14);
xkt2=zeros(0:14);
k1 is the variable and I tried syms, @(k1) and k1=[ ];, sadly nothing worked and either it had problems of converting it into double, or simply wasnt able to use it correctly, if someone with more knowledge about matlab could help me, I would be really grateful.
Sincerely
Jan C. Faber
采纳的回答
Using symbolic k1 and xkt1:
syms k1 xkt1
xg= 7*2*5*1*6*3;
xh= 3/10;
F1=3;
F2=100;
T= 1/500;
for i= 0:14
xkt1(i+1)= xg*sin(2*pi*F1*(k1.*T-i*T));
end
xkt1
% evaluate xkt1(1) at k1 = 0, get a symbolic expression:
subs(xkt1(1),k1,0)
% evaluate xkt1(1) at k1 = 0, get a numeric value:
double(subs(xkt1(1),k1,0))
% evaluate xkt1(2) at k1 = 0, get a symbolic expression:
subs(xkt1(2),k1,0)
% evaluate xkt1(2) at k1 = 0, get a numeric value:
double(subs(xkt1(2),k1,0))
Alternatively, using a cell array of anonymous functions:
xg= 7*2*5*1*6*3;
xh= 3/10;
F1=3;
F2=100;
T= 1/500;
xkt1=cell(1,15);
for i= 0:14
xkt1{i+1}= @(k1)xg*sin(2*pi*F1*(k1.*T-i*T));
end
xkt1
% evaluate xkt1{1} at k1 = 0:
xkt1{1}(0)
% evaluate xkt1{2} at k1 = 0:
xkt1{2}(0)
更多回答（1 个）
xg= 7*2*5*1*6*3;
xh= 3/10;
F1=3;
F2=100;
T= 1/500;
fun = @(k1,i) xg*sin(2*pi*F1*(k1-i)*T);
fun(14,0:14)
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