Find the corresponding value of y when x is a specific value?

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I have a 369 x 2 x 27 matrix. The 369 rows (x value) are from 230:598. I want to find the corresponding y value when x-value is equal 280. Then, make a table with 1:27 on the first column and the corresponding values as the second column. Can anyone please advice me how to do it?
Thank you so much!!

采纳的回答

Voss
Voss 2022-5-18
Maybe this
% a 3D array like yours
M = [(230:598).' rand(369,1)]+reshape(0:5:130,[1 1 27]);
size(M)
ans = 1×3
369 2 27
% find the row of M(:,1,1) where 280 is
row_idx = find(M(:,1,1) == 280,1);
% make the table
T = table((1:size(M,3)).',permute(M(row_idx,2,:),[3 2 1]));
head(T)
ans = 8×2 table
Var1 Var2 ____ ______ 1 0.6688 2 5.6688 3 10.669 4 15.669 5 20.669 6 25.669 7 30.669 8 35.669

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